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solution9_pdf - maini(nm7637 – hw9 – Shneidman...

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Unformatted text preview: maini (nm7637) – hw9 – Shneidman – (12108) 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Find the magnitude of the magnetic force on a proton moving with velocity 4 . 35 Mm / s in the positive x direction in a magnetic field of 1 . 65 T in the positive z direction. Correct answer: 1 . 14996 pN. Explanation: Let : q = 1 . 60218 × 10 − 19 C , vectorv = (4 . 35 Mm / s) ˆ ı = (4 . 35 × 10 6 m / s) ˆ ı , and vector B = (1 . 65 T) ˆ k . vector F = qvectorv × vector B = (1 . 60218 × 10 − 19 C) × bracketleftbig (4 . 35 × 10 6 m / s) ˆ ı bracketrightbig × bracketleftBig (1 . 65 T) ˆ k bracketrightBig × 10 12 pN 1 N =- (1 . 14996 pN) ˆ , so the magnitude is 1 . 14996 pN . 002 (part 1 of 2) 10.0 points An electron is projected into a uniform mag- netic field given by vector B = B x ˆ ı + B y ˆ , where B x = 4 . 2 T and B y = 1 . 6 T. The magnitude of the charge on an electron is 1 . 60218 × 10 − 19 C . x y z v = 3 . 8 × 10 5 m / s electron 4 . 2 T 1 . 6 T B Find the direction of the magnetic force when the velocity of the electron is v ˆ , where v = 3 . 8 × 10 5 m / s....
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This note was uploaded on 01/31/2011 for the course PHYS 111 taught by Professor Moro during the Spring '08 term at NJIT.

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solution9_pdf - maini(nm7637 – hw9 – Shneidman...

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