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solution9_pdf - maini (nm7637) hw9 Shneidman (12108) 1 This...

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Unformatted text preview: maini (nm7637) hw9 Shneidman (12108) 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Find the magnitude of the magnetic force on a proton moving with velocity 4 . 35 Mm / s in the positive x direction in a magnetic field of 1 . 65 T in the positive z direction. Correct answer: 1 . 14996 pN. Explanation: Let : q = 1 . 60218 10 19 C , vectorv = (4 . 35 Mm / s) = (4 . 35 10 6 m / s) , and vector B = (1 . 65 T) k . vector F = qvectorv vector B = (1 . 60218 10 19 C) bracketleftbig (4 . 35 10 6 m / s) bracketrightbig bracketleftBig (1 . 65 T) k bracketrightBig 10 12 pN 1 N =- (1 . 14996 pN) , so the magnitude is 1 . 14996 pN . 002 (part 1 of 2) 10.0 points An electron is projected into a uniform mag- netic field given by vector B = B x + B y , where B x = 4 . 2 T and B y = 1 . 6 T. The magnitude of the charge on an electron is 1 . 60218 10 19 C . x y z v = 3 . 8 10 5 m / s electron 4 . 2 T 1 . 6 T B Find the direction of the magnetic force when the velocity of the electron is v , where v = 3 . 8 10 5 m / s....
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solution9_pdf - maini (nm7637) hw9 Shneidman (12108) 1 This...

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