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Unformatted text preview: taherisefat (mt23852) hw 13 Opyrchal (121012) 1 This printout should have 16 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points An inductor has a 70 . 1 reactance at 87 . 7 Hz. What will be the peak current if this in ductor is connected to a 68 Hz source that produces a 104 V rms voltage? Correct answer: 2 . 70596 A. Explanation: Let : X L = 70 . 1 , f 1 = 87 . 7 Hz , f 2 = 68 Hz , and V rms = 104 V . The inductance is L = X L 2 f 1 = 70 . 1 2 (87 . 7 Hz) = 0 . 127215 H . Thus, the rms current is I rms = V rms X L = V rms 2 f 2 L , so the maximum current is I max = 2 I rms = 2 V rms 2 f 2 L = 2(104 V) 2 (68 Hz) (0 . 127215 H) = 2 . 70596 A . 002 (part 1 of 2) 10.0 points In a purely inductive AC circuit, as in the figure, the maximum voltage is 140 V. L S E If the maximum current is 8 . 35 A at 50 Hz, find the inductance. Correct answer: 53 . 3693 mH. Explanation: Let : V max = 140 V , I 1 = 8 . 35 A , and f 1 = 50 Hz . The inductive reactance is X L = V I 1 = L = 2 f 1 suppressL , so the inductance is L = V 2 f 1 I 1 = 140 V 2 (50 Hz)(8 . 35 A) 10 3 mH H = 53 . 3693 mH . 003 (part 2 of 2) 10.0 points At what angular frequency is the maximum current 2 . 65 A? Correct answer: 989 . 898 rad / s. Explanation: Let : I max = 2 . 65 A The inductive reactance is X L = V I 2 = 2 L, so the angular frequency is 2 = X L L = V I 2 L = 140 V (2 . 65 A)(53 . 3693 mH) 10 3 mH H = 989 . 898 rad / s ....
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 Spring '08
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