sol8 - AMS 540 / MBA 540 (Fall, 2010) Estie Arkin Homework...

This preview shows pages 1–2. Sign up to view the full content.

AMS 540 / MBA 540 (Fall, 2010) Estie Arkin Homework Set # 8: Solution notes 1). (a). Dual solution is w * 1 = 4, w * 2 = 0, w * 3 = 10, objective = 440. Therefore, I would choose to increase the amount of resource 3, it has the highest shadow price. (b). Computing the update z 4 - c 4 = wa 4 - c 4 = - 2 < 0, so x 4 wants to enter the basis. After one pivot we get a new optimal tableasu: z x 1 x 2 x 3 x 4 x 5 x 6 x 7 RHS z 1 11 4 0 0 8 0 10 480 x 4 0 1 2 0 1 1 0 0 20 x 6 0 -1 1 0 0 0 1 -1 18 x 3 0 1 -2 1 0 -1 0 1 16 (c). Computing the new right hand side B - 1 b = (20 , - 2 , 36) so the solution is “optimal” but no longer feasible. We do a dual simplex pivot, with x 6 leaving the basis and x 4 entering. The new optimal tableau is: z x 1 x 2 x 3 x 4 x 5 x 6 x 7 RHS z 1 3 0 0 0 2 4 6 512 x 2 0 -1 1 0 0 0 1 -1 18 x 4 0 3 0 0 1 1 -2 2 4 x 3 0 -1 0 1 0 -1 2 -1 32 (d). Check, the current opt violates the new constraint. Adding the constraint 3 x 1 + 2 x 2 + 2 x 3 + x 4 + x 8 = 80, clean up tableau (to make the basic variables look basic in this new row) and use

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/31/2011 for the course AMS 540 taught by Professor Arkin,e during the Fall '08 term at SUNY Stony Brook.

Page1 / 2

sol8 - AMS 540 / MBA 540 (Fall, 2010) Estie Arkin Homework...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online