MT2_2008 - Chemistry 1A, Spring 2008 Midterm Exam II,...

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Chemistry 1A, Spring 2008 Midterm Exam II, Version A March 10, 2008 (90 min, closed book) Name:__________________________ SID:____________________________ TA Name:_______________________ 1.) Write your name on every page of this exam. 2.) This exam has 20 multiple-choice questions and 3 short answer questions. Fill in the Scantron form AND circle your answer on the exam. 3.) There is no penalty for guessing, so answer every question. 4.) Select one answer for each question. There are no questions with multiple answers. 5.) Show all work to receive credit on short answer questions. Question Page Points Score Multiple Choice 3-5 60 21) Periodic Trends 6 12 22) Molecular Orbitals 7 12 23) Kinetic Gas Theory 8-9 16 Total 100
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Name_______________________________ Page 2 800 600 400 200 IR Red Green Blue UV Wavelength (nm) Color and Wavelength of Light G ° = H ° - T S ° H ° = Σ H ° f (products) - Σ H ° f (reactants) S ° = Σ S ° (products) - Σ S ° (reactants) G ° = Σ G ° f (products) - Σ G ° f (reactants) S = k B lnW Bond Order = (# of bonding electrons - # of anti- bonding electrons) ÷ 2 G ° = - RTln K R S T R H K ° + ° = 1 ln G ° = - nF Є º pX = - log X ] [ ] [ log HA A pK pH a + = E = h ν λν = c λ deBroglie = h / p = h / mv E kin (e-) = h ν - Φ = h ν - h ν 0 = R n Z E n 2 2 E i f =− R 1 n f 2 1 n i 2 x p h/4 π p = mv Particle in a box (1-D Quantum): E n = h 2 n 2 /8mL 2 ; n = 1, 2, 3. .. PV = constant PV = nRT RT E kin 2 3 = M 3RT v rms = E = q + w w = - P ext V E = 3 2 nR T N 0 = 6.02214 x 10 23 mol -1 R = 2.179874 x 10 -18 J R = 3.28984 x 10 15 Hz k = 1.38066 x 10 -23 J K -1 h = 6.62608 x 10 -34 J s m e = 9.101939 x 10 -31 kg c = 2.99792 x 10 8 m s -1 Gas Constant: R = 8.31451 J K -1 mol -1 R = 8.20578 x 10 -2 L atm K -1 mol -1 T (K) = T (C) + 273.15 F = 96,485 C / mol 1 V = 1 J / C 1 nm = 10 -9 m 1 kJ = 1000 J 1 atm = 760 mmHg = 760 torr = 101,325 Pa
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MT2_2008 - Chemistry 1A, Spring 2008 Midterm Exam II,...

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