HW Key _1

HW Key _1 - Chem 111 HW Key#1 Sept 4 2009 A.26 Ek = mv2...

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Chem 111 HW Key #1 Sept 4, 2009 A.26: E k = ½ mv 2 = ½(2.5 x 10 5 kg)(25 km·s -1 ) 2 (1000 m/1 km) 2 = 7.8 x 10 13 kg · m 2 · s -2 = 7.8 x 10 13 J A.29: E P = mgh = (40.0 g)(9.81 m · s 2- )(0.50 m)(1 kg/1000 g) = 0.20 kg · m 2 · s -2 for one raise of a fork For 30 raises, (30)( 0.20 kg · m 2 · s -2 ) = 6.0 J A.30: A.33: The relationship between distance of separation and potential energy for charged particles is given in section A.2, equation 4. Considering the proton and electron beginning at rest and at infinite separation sets the initial total energy to 0. Since the electron is not at rest in a hydrogen atom, its total energy is represented by equation 5: E = E k + E P . We have only calculated the potential energy. The discrepancy between the calculated value of the potential energy, -27.7eV, and the measured amount released, -13.6 eV, is the
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HW Key _1 - Chem 111 HW Key#1 Sept 4 2009 A.26 Ek = mv2...

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