ee3tp4_midterm_solutions_2010

ee3tp4_midterm_solutions_2010 - Question 1 h(t 2 t 2-2 x(t...

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Question 1

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2 2 h(t) -2 2 x(t) t t −∞ h t − x  d or −∞ x t − h  d
2 2 h(t) -2 2 x(t) t h(t-τ) t-2 τ t-τ t+2 t τ x(t-τ) t t 2

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-2 2 x(τ) t h(t-τ) t-2 τ t-τ τ Time reverse h(t) (a) -2 < t < 0 2 t 2 t − d
-2 2 x(τ) t h(t-τ) t-2 τ t-τ τ Time reverse h(t) (b) 0 < t < 2 t 2 0 2 t − d

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Time reverse x(t) (a) -2 < t < 0 0 t 2 2 d 2 2 h(τ) t+2 t τ x(t-τ) 2 τ
Time reverse x(t) (a) 0 < t < 2 t 2 2 d 2 2 h(τ) τ t+2 t τ x(t-τ) 2

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2(c) For what values of t 0 could x t t 0 be the impulse response of a causal system? -2 2 x(t) t x(t - t 0 ) t t 0 t 0 2 x t t 0 must be zero for negative time. Therefore t 0 2.
Question 2 Note that T = 2 and therefore 0 = 2 T = (rad/sec)

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This note was uploaded on 02/01/2011 for the course ECE 3TP4 taught by Professor Drterrencetodd during the Fall '10 term at McMaster University.

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ee3tp4_midterm_solutions_2010 - Question 1 h(t 2 t 2-2 x(t...

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