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Unformatted text preview: Rehman (aar638) – HW03 – sachse – (56620) 1 This printout should have 20 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Decide which of the following regions has area = lim n →∞ n summationdisplay i = 1 π 3 n tan iπ 3 n without evaluating the limit. 1. braceleftBig ( x, y ) : 0 ≤ y ≤ tan 2 x, ≤ x ≤ π 3 bracerightBig 2. braceleftBig ( x, y ) : 0 ≤ y ≤ tan x, ≤ x ≤ π 3 bracerightBig correct 3. braceleftBig ( x, y ) : 0 ≤ y ≤ tan 3 x, ≤ x ≤ π 3 bracerightBig 4. braceleftBig ( x, y ) : 0 ≤ y ≤ tan x, ≤ x ≤ π 6 bracerightBig 5. braceleftBig ( x, y ) : 0 ≤ y ≤ tan 3 x, ≤ x ≤ π 6 bracerightBig 6. braceleftBig ( x, y ) : 0 ≤ y ≤ tan 2 x, ≤ x ≤ π 6 bracerightBig Explanation: The area under the graph of y = f ( x ) on an interval [ a, b ] is given by the limit lim n →∞ n summationdisplay i = 1 f ( x i ) Δ x when [ a, b ] is partitioned into n equal subin tervals [ a, x 1 ] , [ x 1 , x 2 ] , . . . , [ x n − 1 , b ] each of length Δ x = ( b a ) /n . If A = lim n →∞ n summationdisplay i = 1 π 3 n tan iπ 3 n , therefore, we see that f ( x i ) = tan iπ 3 n , Δ x = π 3 n . But in this case x i = iπ 3 n , f ( x ) = tan x, [ a, b ] = bracketleftBig , π 3 bracketrightBig . Consequently, the area is that of the region under the graph of y = tan x on the interval [0 , π/ 3]. In setbuilder notation this is the region braceleftBig ( x, y ) : 0 ≤ y ≤ tan x, ≤ x ≤ π 3 bracerightBig . 002 10.0 points Estimate the area under the graph of f ( x ) = 4 sin x between x = 0 and x = π 4 using five approx imating rectangles of equal widths and right endpoints. 1. area ≈ 1 . 431 2. area ≈ 1 . 451 3. area ≈ 1 . 411 4. area ≈ 1 . 391 correct 5. area ≈ 1 . 471 Explanation: An estimate for the area under the graph of f on [0 , b ] with [0 , b ] partitioned in n equal subintervals [ x i − 1 , x i ] = bracketleftBig ( i 1) b n , ib n bracketrightBig and right endpoints x i as sample points is A ≈ braceleftBig f ( x 1 ) + f ( x 2 ) + . . . + f ( x n ) bracerightBig b n . For the given area, f ( x ) = 4 sin x, b = π 4 , n = 5 , Rehman (aar638) – HW03 – sachse – (56620) 2 and x 1 = 1 20 π, x 2 = 1 10 π, x 3 = 3 20 π, x 4 = 1 5 π, x 5 = 1 4 π . Thus A ≈ 4 braceleftBig sin parenleftBig 1 20 π parenrightBig + . . . + sin parenleftBig 1 4 π parenrightBigbracerightBig π 20 . After calculating these values we obtain the estimate area ≈ 1 . 391 for the area under the graph. keywords: area, sin function, estimate area, numerical calculation, 003 10.0 points Rewrite the sum 4 n parenleftBig 2 + 5 n parenrightBig 2 + 4 n parenleftBig 2 + 10 n parenrightBig 2 + . . . + 4 n parenleftBig 2 + 5 n n parenrightBig 2 using sigma notation....
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This note was uploaded on 02/01/2011 for the course MATH 408L taught by Professor Gogolev during the Fall '09 term at University of Texas.
 Fall '09
 GOGOLEV
 Calculus

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