CH5 Gases 2008 for Web [Compatibility Mode]

# CH5 Gases 2008 for Web [Compatibility Mode] - Chapter 5...

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Chapter 5: Gases • Properties of Gases as Laws (pressure volume Gas Laws (pressure, volume, temperature, moles) ases in Chemical Reactions • Gases in Chemical Reactions • The Kinetic Model of Gases

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Gaseous elements

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Pressure = Force/Area
A barometer

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Boyle’s Experiments Lower Higher ressure Pressure Pressure

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If a fixed amount of gas is released into a larger container, how much force does it exert? As the pressure increases, the volume ecreases 1 / P decreases. V ~ 1/P
If the volume of a gas is constrained to a smaller container, how much force does it exert? As the pressure increases, the volume decreases. P ~ 1/V oyle’s Law: Boyle s Law: P 1 V 1 = P 2 V 2

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Relationship V 1 between volume and ressure P 1 pressure. P 1 V 1 = P 2 V 2 ecrease volume Decrease volume Æ more collisions V 2
• Ex. 1 A sample of gas occupies 21 liters at a pressure of 2.2 atm. What would be the volume if the pressure was increased to 6.2 atm? • Ex. 2 A sample of O 2 occupies 10.0 L at 785 torr. At what pressure would it occupy 14.5 L?

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If the temperature of gas is increased, how will its olume respond (if the pressure is kept constant)? volume respond (if the pressure is kept constant)? harle’s Law: Charle s Law: V 1 /T 1 = V 2 / T 2
The point where a gas would have zero volume!

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If a gas is heated, how much force does it exert f the volume is kept constant)? (if the volume is kept constant)? P ~ T
ombined Gas Law Combined Gas Law (Boyle and Charle’s) P 1 V 1 = P 2 V 2 T 1 T 2

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Re-cap of Gases: Boyle’s Law: Charles’s Law: = P = V T P 1 V 1 P 2 V 2 V 1 /T 1 V 2 / T 2 P 1 V 1 = P 2 V 2 T 1 T 2 ) as equations should make sense: V P T 1) Gas equations should make sense: V, P, T 2) Watch your units! (K, L, atm)
ne standardized set of One standardized set of conditions = STP = 0 o C (273 K) and 1.00 atm (760. Torr)

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• Ex. 3
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CH5 Gases 2008 for Web [Compatibility Mode] - Chapter 5...

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