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Unformatted text preview: P0068_Soln.doc P 1 =. 5 F2 () 0 P 2 =. 1 F 3 ()0 P 3 =. 0 F 4 ()0 Serial system only works if all components work, so we want to know: P1 F F F ( ∩2∩3 ) Since the components fail/succeed independently: P ∩∩ =( P2P3 F2 3 ( F F P1 ()F ) F F () ) 1 The probability of success is one minus the probability of failure (complement): P 1 =− (1 F F () 1 P ) Thus, P ∩ F ( 0 )− 1− 0 0 0 F 2 ) 1 .5 . ( . = 5 ∩ 1 31 4 3 ( F 3=−2( 0 ) 0 ) .1 1 ...
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This note was uploaded on 02/01/2011 for the course BME 335 taught by Professor Dunn during the Spring '10 term at University of Texas.
 Spring '10
 Dunn

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