Equation to propagate

Equation to propagate - (1) c = (b/k) 1/2 = (158 g / 8400...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Equation to propagate: let m=100 ± 1g, M=173.2 ± .1g, k = 8400 ± 100 dynes/cm It takes 4 steps. Step 1: Propagate M/3 Let a = M/3 thus according to rule 1, a= M/3 A ± a = (173.2/3) ± (.1/3) =57.733333….± .03333333…. =57.73 ± .03 g k m T ) 03 . 73 . 57 ( 2 ± + = π Step 2: Propagate (m + M/3) which is (m + a) According to rule 2 ……. . (m+a)= m+ a b = (m + a) ± (m+a) = (m+a) ± ( m+ a) = (100g+57.73g) ± (1g+.03g) = 157.73 ± 1.03 g = 158 ± 1 g 2 1 1 158 2 1 158 2 ± = ± = k g k g T step 3: Propagate the square root part using rule 4
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (1) c = (b/k) 1/2 = (158 g / 8400 dynes/cm) 1/2 = (.1371478174 sec) (2) c/c = (1/2) ((1/158) 2 +(100/8400) 2 ) 1/2 = .00674130994 (3) c = (.1371478174 sec) (.00674130994) = .000924555. = .0009 sec (4) c c = .1371 .0009 sec ) 0009 . 1371 (. 2 = T Step 4: Now we need to deal with the constant using Rule 1 T = 2 (.1371.0009) = 2 (.1371) 2 (.0009) = .8614247056 .00565486677 = .861.006 sec RESULT: T = .861 .006 sec...
View Full Document

This note was uploaded on 02/02/2011 for the course PHYS 206 taught by Professor Pickett during the Spring '11 term at University of Evansville.

Ask a homework question - tutors are online