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Unformatted text preview: a’bd b) F = a’b’c’ + a’c’d + bcd + ac + a’bd The above expression is an AND – OR circuit realization for F. c) F = (a’ + c)(b’ + c + d)(a + b’ + d)(a + c’ + d)(a + b + c’) The above expression is an OR – AND circuit realization for F. 6) A = B = C = 1, so F = (A + B’ + C’)(A’ + B + C’)(A’+ B’ + C) = 1 But, in the figure, gate 4 outputs F = 0, indicating that something is wrong. For the last NOR gate, F = 1 only when all its inputs are 0. But the output of the gate is 1. Therefore, gate 4 is working properly, but gate 1 is connected incorrectly or is malfunctioning. 7) e is the output of the inverter...
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- Spring '08
- Gate, circuit realization, a’bd + ac, minimum solution, following covers