HW8_solutions-1_09

# HW8_solutions-1_09 - Homework#8 ECE 15a Winter 2009...

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Unformatted text preview: Homework #8 ECE 15a Winter 2009 Solutions (5p)1. Construct a 4-to-16 line decoder with five 2-to-4 line decoders with enable. Solution: The input of the 4-to-16 decoder is: X 4 X 3 X 2 X 1 and the output is m0 through m15: 1 2 3 1 en 2-to-4 DEC 1 2 3 1 en 2-to-4 DEC 1 2 3 1 en 2-to-4 DEC 1 2 3 1 en 2-to-4 DEC 1 2 3 1 en 2-to-4 DEC X X 1 X X 1 X X 1 X X 1 X 2 X 3 m4 m5 m6 m7 m0 m1 m2 m3 m8 m9 m10 m11 m12 m13 m14 m15 1 (5p) Problem-2 Solution: First, we express the functions in DNF form: F1 = xyz’+x’zw+y’w’ =xyz’w +xyz’w’+x’yzw+x’y’zw+x’y’zw’+xy’zw’+x’y’z’w’+xy’w’z’ = m13+m12+m7+m3+m2+m10+m0+m8 F2 = x’yzw’+yz’ =x’yzw’+xyz’w+x’yz’w+xyx’w’+x’yz’w’ = m6 + m13+ m5+ m12+ m4 F3 = xy+zw+x’w’ = xyz’w+xyzw’+xyz’w’+xyzw+xy’zw+x’yzw+x’y’zw+x’yzw’+x’yz’w’+x’y’zw’+x’y’z’w’ = m13+m14+m12+m15+m11+m7+m3+m6+m4+m2+m0 Now, we can build these functions by ORing the outputs of a 3-to-8 decoder: 1 2 3 4 5 6 7 1 2 3 4-to- 16 DEC z y x F1 F2 F3 8 9 10 11 12 13 14 15 w (5p) 3. Construct a 16x1 multiplexer with two 8x1 and one 2x1 multiplexers. Use block diagrams....
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## This note was uploaded on 02/02/2011 for the course ECE 15A taught by Professor M during the Spring '08 term at UCSB.

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HW8_solutions-1_09 - Homework#8 ECE 15a Winter 2009...

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