HammondLA8 - A) H0 : = 15 HA : 15 B) (.05)=.25 1-(.25)=.75...

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A) H 0 : μ = 15 H A : μ ≠ 15 B) ½(.05)=.25 1-(.25)=.75 .67,-.67 C) Hypothesis test results: μ : mean of Variable H 0 : μ = 15 H A : μ ≠ 15 Std. Dev. not specified Variable n Sample Mean Std. Err. Z-Stat P-value var1 32 14.521875 0.78894496 -0.6060309 0.5445 D) Fail to reject E) P-value 0.5445 F)  Fail to reject the null hypothesis based on the p-value because it does not lie within the           rejection  region G) At 5% signigicance level there is insufficient evidence to reject the claim that the mean of smokers that quite  permanently is equal to the mean of smokers that did not quite permanently  2.  A) Ho: mean is greater than or equal to 750 (claim) Ha: mean is less than 750
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This note was uploaded on 02/03/2011 for the course ACCT 1100 taught by Professor Matter during the Spring '08 term at Metropolitan Community College- Omaha.

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HammondLA8 - A) H0 : = 15 HA : 15 B) (.05)=.25 1-(.25)=.75...

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