Homework1Solutions - . a a.) 3m (Am) : m A {22% flaw gag...

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Unformatted text preview: . a a.) 3m (Am) : m A {22% flaw gag QM???) $0) 595} (156'8) " CGSA ass ‘3: " 9mg 393% a) £05, Ax $2M 3X = é/23 (3m {MBEX ” 33%” @”%>>€~) QM; {MR fibm} 5 = i/L (s‘m LAX+ git) ~ Sm LAX'%X)> : V1 <W¥+ 49$ AX SEA E3): “3 ; » V, @- assamé $5 = CmA‘X gm EX R G 6:7, i 23,) 5:313:55? ma 3&3 i (522; {Agivk £35; + 035 (Ax, 5%)) : V1 (cos A): {195394 ~3mA>< Esmfix + ma méfiwfifigfi f k @a) 3‘; Cm“): 6‘" +52; 8 ’3‘ X 3 fig‘ifi ,,,,,,,,,, i3) §<>€ {as 59:} r; 3sz éxfififikx} 4;» {$365 2 5m kx émkxjk + (:3; 54>; C5525;ka A: g M {m} 2/4214 A g (aw; g x fig { gsamr m Sax : w :0st $55394 ) X' " xi f} o :4»: 5:635 5; l i . , 325:4; a“ {3mm} : {gm saw wflflx H 9 g. X“’¢ “5...... E 5"? {gag} 3m?! {MK \\ a?“ vfingnX5?n§¥ "VI? ézg’fi’x {aagx & I w _ , *éwsh‘fi *"E; is”? KXM _ s _, 39) jXQWkXc/(X t "QKLesicX4‘iajéééagigg id» ’iw‘x 6mm mag : «A. Xigg 01*“ fi‘na‘va 38$ 3“ a wigmky-if‘ka a) :xmmm ~ x K J“ X X Qua: as: *3“ Wk?» == 23* wax + f2. am w *C» of) fém/W 3% 5&2va ‘3‘ jSFn/firx 5*‘n8C mafia; 5§flfi>€ msficggg; .~. sin 8; jskflvx msé;§"\‘3:oggé ggaéx 5;»; Ex: WWW/W __ f f {pf/WW {:05 c- : QM / s. g ~» {A 2‘ ‘ ~ 4* 4% {:67 :2 cm; 5’”? C" 8} X gm; 3; ‘ 43’ BC “I mgéfl‘é‘fiixv ! a 5% . 2 SM .2 2 Mmé-m ,, WV, MW“ ‘ WW W «WW w — "' : w - “1-... 8% s: mBQCQié 539:3 {:24 X 20%} 0%8} )‘2‘ 2 \/ ‘3? [15' ‘1? a) j mm mm: j iméwaméw 4:" g §§2¥~ {A “339% “3 O “g “g 3 {A 5%? :3 — C23 “'7 «gr géfig} €0$CA+EJK 2£Aflw h EAX é: “a? 2ng @ a9my +07} +k7l‘o jg? m «Xx, , :2 __ J’sx n: X2 Jay M y* GE; J 7 Xéé ) \/ 51f: 0 {mxinkDGK/Wsa x a; 3;. + Q; ,, l< ‘ am “' 45:14; 754 a w L + E ‘ 1 - 3: A» .~i%f§‘ , - s3 :x 3: 6‘5; 2 <52!» GL6. 2“ ‘f ' (9C? Sagas. £62 (Maée'é‘img . (fi}‘€”X/L<w5%xajg‘$m gyfim é) fl‘flflr JC‘ $6-92., (£93 %g as» $53? 3% Lo+jfcf§cesx+ Baggy 5 = ~Aws<é Eéaé‘)? 3% *Aaaézw gmmx wfiéémé‘gia‘ mfiwx +~03¢a¢>4 * 0A8®¥+kk®s¥< Maw? *2an Cr“ Fifi-‘65 rKA) max “k C;- wE“ wk +4483 WK 2‘ W‘X // -m’4+CB%KA% O y I i y m 8%: “a «ragga 32:; .. .vgfig; i Q f :6 u- We . WWMV Wu... W .. gig-Ea ‘3’ . . .Ikx. .Q.j<:c: £35 a ' “a Q?” 3) $£>Z>éé~iy 2: CD =1 “3&0?” j 49 2*02fi4'3y'; E X :XQ C:\Documents and Settings\Jerome Peter Lynch\My Documents\CEE Classes Teaching\CEE511 DynamicsPage lorklb 3:28:14 PM %CEE511 — Homework #1 Solution .%Prof. J. P. Lynch %University of Michigan % Given: A = [l 5 4, 2 7 8, 3 2 5], B=[lO0,042,029], C = [l 3 3], D = [4 7 9 3 12 ll 2 8 8]; % Part (a) mean(D) % Part (b) inv(A) inv(B) % Part (c) [A+B]' % Part (d) det(A) % Part (e) figure; count = O; for x = —S:0.0l:5 count = count + 1; y(count) = 3.5*sin(l.6*x); if count > 1 t(count) = 0.01 + t(count—l); else t(count) = ~5; end end plot(t,y); UntitledZ January 12, 2004 Page 1 3:28:54 PM aIlS BIIS 8118 a115 alls H C) H H U1 H 21 .1111 .9048 .6667 .8095 .0000 11 10 .8095 .3333 .6190 .2813 .0625 14 .5714 .1429 .0625 .1250 \3.\\ .\.\ .\x\\\\ K\\ \.\.\ \\\\\ \\ ...
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Homework1Solutions - . a a.) 3m (Am) : m A {22% flaw gag...

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