Ch_12-1_Concentratiion_Units (2)

Ch_12-1_Concentratiion_Units (2) - Molality = ? mol solute...

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CONCENTRATION OF SOLUTIONS Molarity = M = ? Mass percent = ? Mole Fraction of A = ? Molality = m = ? mol solute L solution mol solute kg solvent A A A B n n n χ = + 100% g solute x g solution (Review) (New)
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• Common commercial acids and bases are aqueous solutions. . CONCENTRATION OF SOLUTIONS CALCULATIONS •Frequently the mass percent and density are specified. 95% by mass means 2 4 2 4 2 4 95 95 100 95 5 g H SO g H SO or g solution g H SO g solvent + Molarity = ? mol L solution 2 4 95 100 g H SO g solution = 1.84 1 g solution x mL solution 3 10 1 mL solution x L solution 2 4 2 4 1 98.1 mol H SO x g H SO =17.8 M EXAMPLE 1: Sulfuric acid: 95% solute by mass; density 1.84g/cm 3 ; and MW = 98.1 g/mol. What are the molarity (M), the molality (m), and mole fraction ( χ ) of sulfuric acid?
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CONCENTRATION OF SOLUTIONS CALCULATIONS
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Unformatted text preview: Molality = ? mol solute kg solvent 2 4 95 5 g H SO g solvent = 3 10 1 g solvent x kg solvent 2 4 2 4 1 98.1 mol H SO x g H SO = 194 m Mole Fraction of H 2 SO 4 = ? 2 4 2 4 2 4 2 H SO H SO H SO H O n n n = + 2 4 2 4 2 4 2 4 95 1 0.968 1 98.1 H SO g H SO mol H SO n x mol g H SO = = 2 2 2 2 5 1 0.277 1 18.02 H O g H O mol H O n x mol g H O = = 2 4 0.968 0.777 0.968 0.277 H SO = = + 2 1 0.777 0.223 H O = -= PRACTICE PROBLEM 1: Aqueous concentrated ammonia (NH 3 ): 28% ammonia and density = 0.90 g/cm 3 . What are the molarity ( M ), the molality ( m ), and mole fraction ( ) of ammonia? Answer: 15 M , 23 m , and 0.29....
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Ch_12-1_Concentratiion_Units (2) - Molality = ? mol solute...

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