review 8 answers - Chem 100 Dr Anna Toy-Palmer Chapter 8...

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Chem 100 Dr. Anna Toy-Palmer Chapter 8 Review Problems 1. 3.25 mol of solid magnesium are reacted with 1.82 mol of aqueous hydrochloric acid to form aqueous magnesium chloride and hydrogen gas. How many moles of hydrogen gas are formed? What is the limiting reactant? Mg(s) + 2HCl (aq) MgCl 2 (aq) + H 2 (g) Conversion factors: 1 Mg ≡ 1 H 2 , 2 HCl ≡ 1 H 2 2 2 H mol 25 . 3 Mg mol 1 H mol 1 Mg mol 25 . 3 = X 2 2 H mol 910 . 0 HCl mol 2 H mol 1 HCl mol 82 . 1 = X Answer: 0.910 mol H 2 is formed, HCl is the limiting reactant 2. 25.4 g of solid aluminum are reacted with 225 ml of 1.57 M sulfuric acid solution to form aqueous aluminum sulfate and hydrogen gas. How many grams of hydrogen gas are formed? What is the limiting reactant? 2Al(s) + 3H 2 SO 4 (aq) Al 2 (SO 4 ) 3 (aq) + 3H 2 (g) Conversion factors: 2 Al ≡ 3 H 2 , 1 H 2 SO 4 ≡ 1 H 2 Al: 26.981 g/mol H 2 : 2 X 1.00794 g/mol = 2.01588 g/mol H 2 SO 4 : 225 ml solution, 1.57 M sulfuric acid concentration 2 2 2 2 H g 85 . 2 H mol 1 H g .01588 2 Al mol 2 H mol 3 Al g 981 . 26 Al mol 1 Al g 4 . 25 = X X X 2 2 2 4 2 2 4 2 4 2 H g 712 . 0 H mol 1 H g .01588 2 SO H mol 1 H mol 1 solution L 1 SO H mol 57 . 1 solution ml 1000 solution L 1 solution SO H ml 25 2 = X X X X Answer: 0.712 g H 2 is formed, H 2 SO 4 is the limiting reactant 3. 25.7 g of nitrogen gas are reacted with 32.2 g of oxygen gas to form nitrogen monoxide
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