review 13 anwers

review 13 anwers - Chem 100 Dr. Anna Toy-Palmer Ch 13...

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Chem 100 Dr. Anna Toy-Palmer Ch 13 Problems 1. What is the mass percent of a solution when 15.4 g of sodium phosphate is dissolved in 56.5 g of water? 4 3 PO Na % 4 . 21 % 100 ) g 4 . 15 g 5 . 56 ( g 4 . 15 Percent Mass = + = X 2. How many milliliters of a 15.5% mass percent potassium carbonate solution to obtain 3.65 g of potassium carbonate? (Assume the density of the solution is 1.00 g/ml) 3 2 3 2 3 2 CO K g .5 23 solution g 1.00 solution ml 1.00 X CO K g 15.5 solution g 100 X CO K g 3.65 = 3. What is the mass percent of a 0.15 M sucrose (C 12 H 22 O 11 ) solution? (Assume that the density of the solution is 1.00 g/ml) C 12 H 22 O 11 : [(12 X 12.011)+(22 X 1.00794)+(11 X 15.9994)] g/mol = 342.30 g/mol solution sucrose 5.1% % 100 sucrose mol 1 sucrose g 342.30 solution g 1.00 solution ml 1.00 X solution ml 1000 solution L 1 X solution L 1 sucrose mol 0.15 = X X 4. 25.3 ml of a 3.5% mass percent sodium hydroxide solution is neutralized by 18.7 ml of an acetic acid solution. What is the mass percent concentration of the acetic acid solution? (Assume that the density of solution for both the sodium hydroxide solution and the acetic acid solution is 1.00 g/ml) NaOH (aq) + HC 2 H 3 O 2 (aq) H 2 O (l) + NaC 2 H 3 O 2 (aq) Equivalence: 1 NaOH ≡ 1 HC 2 H 3 O 2 Molar mass: NaOH: (22.989 + 15.9994 + 1.00794)g/mol = 39.996 g/mol HC 2 H 3 O 2 : (4X1.00794 + 2X12.011 + 2X15.9994) g/mol = 60.053 g/mol Obtain moles of NaOH from mass percent and convert to grams of acetic acid.
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review 13 anwers - Chem 100 Dr. Anna Toy-Palmer Ch 13...

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