AEM2012_Exam2_Spring2008_Soln

# AEM2012_Exam2_Spring2008_Soln - AEM 2012 — Examination#2...

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Unformatted text preview: AEM 2012 — Examination #2 — Spring 2008 Problem #1: Mass m is placed in front of a linear spring at A and “sho " through loop BC. The spring is compressed a distance A from its unstretched length and the force that the track exerts on the mass at the top of the loop (point C) is at least two—thirds of the weight of the mass. The entire track is smooth. What is the minimum value for the spring constant k? Express your answer in terms of the compression distance A, the gravitational constant g, the mass m, and the loop radius R. Hen FﬁO a; mass Q C: A % l 64 M‘aen i4: my...” ('13 NM. R a - . __ . L13 éCZ) 1 MVL cam‘ni e L 2, " timer " m F=mm V 2.. ‘2 F“:- N +MZ :— M .5; R. >, 3-. N 3 W3 (3) 0r Vol >, S—L‘R CH3. AEM 2012 — Examination #2 — Spring 2008 Problem #2: A 10 gram bullet is ﬁred with an initial speed of 260 meters/ second. A 2 kilogram block is initially at rest until the bullet hits and passes through the block. After the bullet penetrates the block, the block slides a distance of 0.2 meters along the ﬂoor until coming to rest (see ﬁgure below). The coefﬁcient of kinetic ﬁiction between the block and the ﬂoor is M = 0.3. Find the exit speed of the bullet after piercing the block. Mb: ‘0‘}: .D\ qu M3 = QKOX Vb -.-: aw ”/5 F————0.2m—————>i AEM 2012 — Examination #2 — Spring 2008 Problem #3: A 28-g steel-jacketed bullet is ﬁred with a velocity of 650 m/s toward a steel 5:30 mm plate and ricochets along path CD with a [i f velocity 500 m/s. Knowing that the bullet “ .t k E {a E leaves a 50-mm scratch on the surface of the a K E ‘ . D plate and assuming that it has an average 900 , “ e \\ E (w i» a“ ”‘ speed of 600 m/s While in contact With the r“ ‘e K J j; , gggggg mt plate, determine the magnitude and direction , , , i of the impulsive force exerted by the plate on - the bullet. Implu —- \$4me xm Ballet 1 c /. v0 5 ~ A y M 3 u. A" 8 ohm. - LoSO‘: Q 223° 6 s' 20‘? \/ 5mm 0°? ‘ \o"c yﬂ— b ca: 1~ m a ~°= 5 (cm 1 +\$m «i , . V. 0- LV\ I i .h 1 ° ° -‘ 1 : m VA Cars 2.0 + j F1 ﬁe =- MVSDLO\$lD (2) (VW\‘ h \l a D 'L t ’ SOMM ' Y‘A \$4 245 Sn“ . O -\ J‘ A " 4v 3 ﬁx“; = m vwssmm (37, N mom’s) a "‘ . cEW‘ avg ‘L 2‘. i33>¢l0 s _‘ \ a .____.=__________———-:- (a!) => (YANG = :‘g 7'}ch = __L [wv‘ Lcs\o°- MVA 6982.0] 1: ‘l; D .2: - E‘ifl’i Kkl i: (3) =9 LE )Mo = ‘1‘: 5 E5 Ab : :‘E. [WVDE’MOO 4.va \$1‘AZO° 2'. “>3.“ \Lh" a fa \EE -_- (Ekﬁtﬁlm 4: New»! tyranny»: 9b I039“ o 9 = {gm-(3.1“): Loam ...
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