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Lec12

# Lec12 - of(V oc I sc and R th Fig 12-6b V oc ’ is the...

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Lecture 12 figures 1 Fig. 12-1: A linear network containing an arbitrary number of sources and resistors can be reduced to a series combination of a voltage source and a resistor. We call this the Thévenin Equivalent network. Fig. 12-2: Similarly, we can reduce the linear network to a parallel combination of a current source and a resistor. We call this the Norton Equivalent network. Fig. 12-3: A circuit consisting of voltage source, a series resistor, and a load. Fig. 12-4: I-V plot for the network consisting of a voltage source and a series resistor.

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Lecture 12 figures 2 Fig. 12-5: A network consisting of independent sources and resistors. Use a series of source transformations and combinations of elements to find the Thévenin equivalent network. Fig. 12-6: The circuit of Fig. 12-5. We will now find the Thévenin equivalent network by finding two
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Unformatted text preview: of (V oc , I sc , and R th ). Fig. 12-6b: V oc ’ is the open-circuit voltage due to the voltage source alone. Fig. 12-6c: V oc ’’ is the open-circuit voltage due to the current source alone. Fig. 12-6d: I sc ’ is the short-circuit current due to the voltage source alone. Fig. 12-6e: I sc ’’ is the short-circuit current due to the current source alone. Fig. 12-6f: Turn off the independent sources to determine R th directly. Lecture 12 figures 3 Fig. 12-7: A network containing dependent and independent sources. = V oc = 0 Fig. 12-7a: Choose an open circuit load to find V oc . Fig. 12-7b: Choose a short circuit load to find I sc . = I sc = 0 Fig. 12-7c: The Thévenin equivalent network of the network in Fig. 12-7. Fig. 12-7e: Alternatively, turn off the independent sources to find R th directly....
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Lec12 - of(V oc I sc and R th Fig 12-6b V oc ’ is the...

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