Lec14

# Lec14 - Lecture 14 figures 2 Fig. 14-6: We will reduce the...

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Lecture 14 figures 1 Fig. 14-1: A simple load resistor attached to a non-ideal voltage source. We will determine the power delivered to a load resistor for various values of R L . Fig. 14-2: A simple load resistor R L attached to a non-ideal voltage source. We will determine the power delivered to a load resistor as a function of R L , and then optimize this power. Fig. 14-3: This optimization applies to a load resistor attached to a non-ideal current source as well. Fig. 14-4: A plot of the Power P L as a function of R L . The optimum power is delivered to the load resistor at R L = R s . This optimum power is P L = V s 2 /4R s . Fig. 14-5: A load resistor R L is connected to a network.

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Unformatted text preview: Lecture 14 figures 2 Fig. 14-6: We will reduce the network to its Thévenin equivalent by finding the linear relation between V AB and I L (Method III). Fig. 14-7: As we have shown before, the linear relation between I L and V AB is I L = –V AB /R th + Vs/R th . Fig. 14-8: The Thévenin equivalent of the network in Fig. 14-6, with a load resistor R L attached. We set R L = R th to optimize the power absorbed. Fig. 14-10: The Thévenin equivalent of the network in Fig. 14-6. Fig. 14-9: We return to the network of Fig. 14-6, which we will reduce to its Thévenin equivalent by finding V oc and I sc (Method II)....
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## This note was uploaded on 02/06/2011 for the course ECE 201 taught by Professor All during the Spring '08 term at Purdue.

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Lec14 - Lecture 14 figures 2 Fig. 14-6: We will reduce the...

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