tele - 12 12 csc πt cot gπtdt = csc u cot gudu = −...

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Unformatted text preview: 12 12 csc πt cot gπtdt = ∫ csc u cot gudu = − ∫ d (csc u ) ∫ ππ ππ 1 6 6 6 1 2 π π Trước hết đặt u = πt vậy suy ra du = πdt Nên ta có: π 12 ∫ csc u cot gudu ππ 6 Do d csc u = − csc u. cot gu du 1 ∫ d (csc u ) ππ 6 Nên − π 2 π 12 1 − ∫ d (csc u ) = − csc u Vậy cuối cùng ta có ππ π 6 π 2 π 6 =− 1 π π 1 (csc − csc ) = π 2 6 π ...
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This note was uploaded on 02/06/2011 for the course MATH 101 taught by Professor Doll during the Spring '11 term at Evergreen Valley.

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