quiz1_07_solution - MECH 310 Thermodynamics I American...

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MECH 310 Thermodynamics I November 20, 2007 American University of Beirut, Fall 2007 Handout # Quiz 1 Solution Quiz 1 Solution Problem 1 (25 points) Two kilograms of water are contained within a piston-cylinder arrangement. The piston is weightless and undergoes frictionless motion. See Figure 1. At the initial state, there are equal masses of liquid and vapor initially. The system is (process 1) slowly heated to a position where the piston is locked, and then (process 2) the system is cooled to the saturated vapor state at 50 C. The atmospheric pressure is p a = 101 . 4 kPa. (a) Is process 1 isothermal, isobaric, or isochoric? Why? What about process 2? why? (b) Draw the processes on a p - v diagram, and (c) Evaluate the work done during the process. H 2 O H 2 O vacuum partition H 2 O p a p a Figure 1: Schematic for problem 1. Solution (a) Process 1 is isobaric since force balance on the piston yields p = p a , where piston inertia is neglected due to the slow heat addition. Process 2 is isochoric since both mass and volume are fixed during this process. (b) See Figure 2. (c) State 1 corresponds to saturated mixture at p = p a , so that T 1 = 100 C. Noting that x 1 = 0 . 5, then v 1 = v f ( p 1 ) + x 1 ( v g ( p 1 ) - v f ( p 2 )) = 0 . 0010435 + 0 . 5(1 . 673 - 0 . 0010435) = 0 . 837 m 3 /kg. The volume at state 1 is therefore V 1 = mv 1 = 2 kg × 0 . 837 m 3 /kg = 1 . 674 m 3 .
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This note was uploaded on 02/07/2011 for the course MECH 310 taught by Professor I.l during the Fall '08 term at American University of Beirut.

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quiz1_07_solution - MECH 310 Thermodynamics I American...

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