solved_problems - 9—](L Determine the equivalent state of...

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Unformatted text preview: 9—](L Determine the equivalent state of stress en an eletttenL if the ele 111cm 15 enenled 3U ee|1111e1eluekwtse from ' 0'3 P“ ‘Lht: elcntertl shuwn. Use the HII'L‘HH-ll'al'lHfilrlllaiiilll equations. 95H psi 0,-0 a,--301}psi fn—mpnl 9-30“ [I 0' 0' *6 . fl'r = “j ’ +J2—1m29+1‘,,am 25' ._ 0.. -3300] I all) :m+{—-eos{fifl‘)+95{hin{fifl°} -T4Bpll All: t;-,-=—{E'--—£L]sin29+fJ,mS 23 “15° r"- D-i‘ 3‘1" rci I-li 2 hit {WHHDWMGD‘}: 3451135 Ana Y-flg fui a, a seams-1 29 n-L—z-st-{flg—mjms {60°}—95LI3:'||1I[60°}|= —1050 psi An: X 9—H. The state ef stress at a paint is shewn en the element. Determine {a} the principal 5111155125 :1 ml {h} the I'I'Irtxitnuttt ill—plane shear stress and average Iterttml stress at the peint. Speeify the urieltttttien ef the element in each ease. 6|) MPu 9E] MPa 45 MPH. fl.=flM-Pt e, uth rfl=3usm .3 UL: _ 21%.flio1’{;;_4}i+tfll f =i5;6fli fils—é-deHm; lfi = 53.0 MFI Am .51 =-6s.n MP: An 13th mm ul prinn'pll m: flank 1-591" H5 I'm W419. =L=—m—un.sm fl‘flfl ta. 4w“: tfi—t—fiumz I s, =um, 433.11 "‘5 fir- UquJ-tlodewmimmpmmuphneofa. “5;; a F a -' If I15- F —';—|’- 4- ‘Tim: 19+ tuninlfl. win: 3 I 1431'“ 45+Hm e—r—m d- 2 2 DUI 193F440 Bin. 29.11“ =- 510 MP]. “mini: 6,; = I13“ Am Ind v9” =-—15\.l' has '1'} t... -1J("—‘1-LEJ?rr.,' n rst'fithLarJI =msum all ..-p_ 1 2 a". 1 tr, +crz i lid-{45¢} 2 2 Urination ormmm In- plasma: smut = £1.59 MP: 1.1! mm. a: i—J—d' _ m - F—--—-—-M' ("mm - 4.5!: 1., an H, = -3lJ.l‘ l.- M E. I 59.9“ All By ahllnfl‘hn. inn-dc: :0me don“. t... In: maniade shown. 9—59. Solve I"1'ob.L}—1Hu5il1g Mohr's circle. RUG psi 3" mu}: _t}-3oor_lmlmii 5 a“ 2 2 950 pm R = {(150)’ + {9501‘ = 961369 psi F‘Bffsg M' 393‘“: p = m" E = 8|.02’i'4‘ 150 a: lW—W—SLM'M“ = 38.973” II;- z—DfilfMBms 38.!13°— 150=—IQSpIi All g”. -ML‘J-eyflnssmr =. 505 pt! An. :3,- - 961.?39um 38.913-150-598pai All Ml Solve Prob. lJ—l_“- using Mohr‘s circle. m MPH fl‘w’ =M-4-5MPI 30mm 2 2 H = {45 +1.5? + (3H? = 60.46“? MB: 45 MPH In I fiDAfiT—TJ = 53.1} MP! All: in = -fi(}.4€|T-1.5 = 4531'! MPH. Am _ 30 2 = an I a" [45 +1.5:- flpl =14? Wk:- Au 'l-' ... I 60.5 HP! A.“ II-l- a... s 430 up: an - 1} it! =- 90“ —Im ‘ " [45 +1.51 in mm 53.5w“?!- 4.1] v 7:” HF. 7.52113 H9- 5 H‘fl'n ...
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solved_problems - 9—](L Determine the equivalent state of...

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