Chem 112

# Chem 112 - 282417.3 mol J 10 4.07 mol 6.939 q J 14630 C...

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CHM 11200 Spring 10 Chapter 10 Worked Lecture Examples

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Example 1 (Practice Problem 10.1, p 380) 2 normal b.p. occurs when vapor pressure equals 1 atm (~−43°C) b.p. at 0.40 atm ~−62°C
Example 2 (Practice Problem 10.2, p 382) 3 gas solid gas solid is deposition deposition is endothermic

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Example 3 (Practice Problem 10.4, p 387) 4 Calculate the heat absorbed when 125 g of water at 72.0°C is converted to steam at 186.4°C. The specific heat of water is 4.18 J/(g °C), the heat of vaporization of water is 4.07 x 10 4 J/mol, and the specific heat of steam is 2.02 J/(g °C) 72.0°C water 100.0°C water 100.0°C steam 186.4°C steam heat heat vaporize ( 29 O H mol 6.939 g 18.0152 mol 1 O H g 125 2 2 =
Example 3 (cont’d) 5 ( 29 ( 29 ( 29 ( 29 ( 29 J 21816 C 100 - C 186.4 C g J 2.02 g 125 q J

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Unformatted text preview: 282417.3 mol J 10 4.07 mol 6.939 q J 14630 C 72-C 100 C g J 4.18 g 125 q steam heat 4 water boil water heat = ⋅ = = × = = ⋅ = q total = q heat water + q boil water + q heat steam q total = 14630 J + 282417.3 J + 21816 J = 318863.3 J 5 Example 4 (Practice Problem 10.9, p 396) 6 Arrange the following liquids in order of increasing boiling points: CHBr 3 , CHCl 3 , CHI 3 CHCl 3 <CHBr 3 <CHI 3 Example 5 (Practice Problem 10.11, p 397) 7 Consider the substances CO and HF. Which has the stronger intermolecular forces? Which has the higher melting point? Boiling point? Vapor pressure?...
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Chem 112 - 282417.3 mol J 10 4.07 mol 6.939 q J 14630 C...

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