{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# Assignment_1_Answer_Key - can write{x|(x є U(x{0,2,3,4,6...

This preview shows pages 1–2. Sign up to view the full content.

Assignment 1 Answer Key Assume the natural numbers include 0, you were not penalized if you assumed otherwise. 1) 0, 3 or 6 would be acceptable answers 2) {}, {0}, {0, 1, 2, 3, 4} or C would all be acceptable answers 3) This is actually the same as #2, so the same answers are acceptable. 4) { (0,0) } and {(0,0), (0,3) } are examples of acceptable answers. (0,0) is not because it is an element of a subset of BxB not a subset of BxB 5) 3 6) There are more elements in A than B, so this is impossible. 7) Example: A -> B { (0,0), (2,3), (4,3), (6,6) } 8) {2,4} 9) Universal set has not been defined, but if we consider U to be the universal set we

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: can write: {x| (x є U) /\ (x ? {0,2,3,4,6} ) } 10) { {}, {0}, {3}, {6}, {0,3}, {0,6}, (3,6}, {0,3,6} } 11) 10 (or 9 if you excluded 0 from the set of natural numbers) 12) The cardinality of the power set of a set of cardinality x is 2 x . Since {a} = 4, we calculate 2 4 = 16. 13) f(6) = 6 14) g(5) = 7 15) Basis: n = 0; 0 3 = 0 2 *(0+1) 2 /4 = 0. Thus the statement is true for the base case n=0. Hypothesis: P(s) = Induction: for n = s+1 = = = 16) Basis: n = 0; 0 (0+1) = 0 = . Thus the statement is true for the base case n=0. Hypothesis: P(s) = Induction: for n= s+1...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern