1013_chap16

# 1013_chap16 - ME240 Agendatoday...

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d td ME 240 Agenda today Conservation of Linear Momentum and Impacts 6 2) (16.2) HW: 16.34, 16.46 Supplemental Problems: 16.35, 16.42

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Problem 16.53. A .12 oz bullet hits a suspended 15 lb block of wood and becomes embedded in it. The attachment wire rotates 7deg in response. What was e bullet’s velocity? the bullet s velocity? 2 12
Problem 16.55. A 12,000 bus traveling at 18 ft/s collides with a 2800 car v B =18 ft/s collides with a 2800 lb car traveling at vC=33ft/s. The vehicles entangle and slide with a kinetic friction =0.6. k 0.6. a) What is velocity after collision? b) What is the final position after they op sliding? stop sliding? 2 13

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Direct Central Impact Occurs when contacting surfaces are oriented so that reaction R is parallel to line along with 2 objects are traveling and is directed toward the center of mass Conservation of momentum: i t it fter impact: = prior to impact: after impact: (No external forces) 2 mv  1 Two unknowns ne equation Direct central pacts: AA BB   one equation impacts:
Direct Central Impact

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## This note was uploaded on 02/07/2011 for the course ME 240 taught by Professor Zinn during the Spring '07 term at Wisconsin.

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1013_chap16 - ME240 Agendatoday...

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