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PHY 201 - Test 1

# PHY 201 - Test 1 - Physics 201 084 NAME Given a tablespoon...

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30 degrees 60 degrees +Q1 Physics 201 TEST 1 084 NAME:_________________________ Given a tablespoon ( 15 cm 3 ) of water, find : What is the mass of one tablespoon of water is ( assume the density of water is 1000kg/m 3 ) V water 15cm 3 = The density of water is ρ water 1000 kg m 3 = the mass of water in is m water ρ water V water = m water 15gm = What is the charge due to the electrons on 1 molecule of water? The number of electrons in one molecule of water( H 2 O) is the sum of electrons in 2 atoms of hydrogen , N e_H 1 = ,and the nuimber of electrons in one atom of oxygen, N _e_O 8 = so N e_water 2 N e_H N _e_O + = N e_water 10 = so the charge due to the elecrrons in 1 molecule of water is Q H20 10 1.602 - 10 19 - C ( 29 = Q H20 1.602 - 10 18 - × C = What is the total charge due to all the electrons in 15 cm 3 of water? so We determine the number of moles of water in a volume of V water 15cm 3 = M mol_H 1amu = The molecular mass of hydrogen is The molecular mass of 0xygen is M mol_O 16amu = The molecular mass of water is M mol_water 2 M mol_H M mol_O + = M mol_water 18amu = The number of moles of water is n water m water M mol_water = n water 0.833 mol = The number of water molecules is N water N a n water = N water 5.017 10 23 × molecules = The total electrons is N e N water N e_water = N e 5.017 10 24 × electrons =

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x y - Q2 30 0 30 0 - Q3 * Given the dipole below of charge |Q| and separation “a” Determine the E field (magnitude and direction) at a point “P” along the perpendicular axis of the dipole E plus E neg Q 4 π ε 0 a 2 2 R 2 + the only component that survives is the +y-component E y_plus E plus ( 29 sin θ ( 29 where sin θ ( 29 a 2 a 2 2 R 2 + 1 2 E totaL  2 Q 4 π ε 0 a 2 2 R 2 + a 2 a 2 2 R 2 + 1 2 j E totaL  Q a 4 π ε 0 a 2 2 R 2 + 3 2 j What direction would the force on an electron placed at “P” be in?
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