ConvectionCoolant_part1

ConvectionCoolant_part1 - the fact that q is usually given....

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ENU 4134 – Convection to Coolant – Part I D. Schubring October 27, 2010
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Learning Objectives I 3-e Apply knowledge of single-phase and two-phase convective heat transfer to convection from fuel rods to coolants, including adjustments to correlations regarded in assembly geometry I 5-b Use correlations and/or models to analyze problems in nuclear thermal hydraulics I 5-e Identify most critical TH parameters/phenomena to investigate/analyze to ensure safe and efficient reactor operation
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General Equation for T co - T m Convective heat transfer is typically understood through the heat transfer coefficient: q 00 co = htc ( T co - T m ) (1) T co - T m = q 00 co htc = q 0 2 π R co htc (2) Computation of htc can be non-trivial, particularly for the 2-phase case, but this equation is general for any htc . Solution of the nuclear TH (single-channel analysis) problem is greatly aided by
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Unformatted text preview: the fact that q is usually given. Must consider adjustments to htc due to rod bundle geometry. Example Problem I P = 14.608 MPa I Geometry: P = 12 mm, D =10 mm, R fo = 4.6 mm, R ci = 4.7 mm I htc g = 5000 W m-2 K-1 I Equation for htc (heat transfer coecient) (Weisman 1 , Schrock and Grossman 2 ) I k c = 20 W m-1 K-1 and k f = 3 W m-1 K-1 I q = 25 kW/m I m = 0 . 15 kg/s (per channel) I T 1 = 320 C , T 2 = T sat = 340 x 2 = 0 . 2 Equations for Solution T co-T m = q 2 R co htc (3) T ci-T co = q 2 k c ln R co R ci (4) T fo-T ci = q 2 R g htc g = q ( R ci + R fo ) htc g (5) T max-T fo = q 4 k f (6)...
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ConvectionCoolant_part1 - the fact that q is usually given....

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