# HW6_S - HW 6 1. The Fourier transform of a signal is ECE...

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DKL:4/25/10 HW 6 1/3 HW 6 ECE 3704 Due 4-13-10 1. The Fourier transform of a signal is (a) (10) Find the signal x ( t ) . Solution X ( ω ) = Π ω 10 = 1 2 π 2 πΠ ω 10 x ( t ) = 1 2 π 10Sa 10 t 2 = 5 π Sa 5 t ( ) (c) (5) Find the energy in the signal. Solution E = 1 2 π X ( ω ) 2 d ω −∞ = 1 2 π 1 2 d ω 5 5 = 10(1) 2 π = 5 π (d) (5) What is the bandwidth of this signal? Solution bandwidth = 5 rad/sec (e) (5) What is the Nyquist sampling frequency of this signal? Nyquist frequency = 10 rad/sec

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DKL:4/25/10 HW 6 2/3 (f) (10) Suppose the sampling frequency is ω s = 15 rad/s
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## This note was uploaded on 02/07/2011 for the course ECE 3704 taught by Professor Odenaal during the Spring '08 term at Virginia Tech.

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HW6_S - HW 6 1. The Fourier transform of a signal is ECE...

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