RusliWPS 417 - Problem 3 - Multiple Effect Evaporators - GRADED

RusliWPS 417 - Problem 3 - Multiple Effect Evaporators - GRADED

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SUMMARY Case Study 1 The claim is valid, and the saving is only around 5.1% Steam Savings (%) (Refer to Case Study 1 Tab and the value is highlighted in turquois green color) Case Study 2 Base Case Case Studies 1) Feed Temperatures (°F) 183.00 185.00 180.00 #Note: I assume that there is Steam Economy 2.398 2.538 2.509 # The new temperatures Capacity (lb/hr) 69357.1 69357.1 69357.1 # So, I use the values g Percent Saving (%) - 5.50 4.44 2) Solids Content (%) 14.50 13.00 16.00 Steam Economy 2.398 2.546 2.506 Capacity (lb/hr) 69357.1 78733.9 59980.2 Percent Saving (%) -6.91 17.23 Explanations: CS2 (T = 185 °F) CS2 (T = 180 °F) CS2 (Solids = 13.0%) CS2 (Solids = 16.0%) The claim is valid because the condensate from the Effect 1 is being flashed and reused steam supply in Effect 3. Therefore, some of the heat value from the condensate are bein This process will in turn results in saving of the steam used. The steam usage results in 5.50% savings because the feed temperatur feed temperature. The higher temperature means that less energy or ste liquor to the same solids content as in the base case. The steam usage results in 4.44% savings because the evaporators con flash tank. There is still some savings even though the feed temperature feed temperature. The lower solids content hurts the steam usage. It uses 6.91% more stea solids content means that there are more water to be evaporated. More that more steam is needed. The flash tank does not help that much in th The higher solids content helps steam savings up to 17.23% compared t content means that there are less water to be evaporated to reach the sa content. The flash tank also play a significant role in the high steam savi
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4.93 is a mistake in the question statement. s to be tested is in °C, but they are very close to the base case temperature in °F given but in °F instead of °C. for the ing utilized. re is higher than the base case eam is required to evaporate the nfiguration includes the new e is lower than the base case am than the base case. Lower water to be evaporated means is problem. to the base case. A high solids ame base case percent solids ing.
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Evaporator Simulator ® Base Case 966.90 Vapor out (lb/hr) 24476.2 267.02 Steam Pressure (psia) 39.85 933.85 Steam in (lb/hr) 28923.3 Effect Pressure (psia) 16.35 217.36 4.64 222.01 Liquor out (lb/hr) 90642.9 Liquor out (lb/hr) Solids (lb/hr) 23200 Solids (lb/hr) Solids out (%) 25.59 Solids out (%) T (°F) Δ 45.02 T (°F) Δ 222.01 Clean condensate flow (lb/hr) A Three Effects Evaporator Simulator by Jannov Rusli ©2008 Heat vap out (Btu/lb), Vapor temp in (°F) Heat vap out (Btu/lb), λ Sat'd Effect Temp (°F) Tv BPR (°F) Effect Temp (°F) TL Temperature (°F) Temperature (°F) Effect 1
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987.48 Vapor out (lb/hr) 21380.8 217.41 Effect Pressure (in Hg vacuum) Effect Pressure (psia) 8.28 Effect Pressure (psia) 184.42 3.41 187.83 115119.2 Liquor out (lb/hr) 136500.0 23200 Solids (lb/hr) 23200 20.15 Solids out (%) 17.00 29.58 T (°F) Δ 17.59 187.83 166.82 28923.3 Dirty condensate flow (lb/hr) 24476.2 λ Vapor temp in (°F) Vapor temp in (°F) Sat'd Effect Temp (°F) Tv Sat'd Effect Temp (°F) Tv BPR (°F) BPR (°F) Effect Temp (°F) TL Effect Temp (°F) TL Temperature (°F) Effect 2 Effe
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999.80 Vapor out (lb/hr) 23500.0 Cons 184.41 a b c d 19.3 e 5.22 f 164.05 g 2.76 166.82 PC A1 Feed flow rate (lb/hr) 160000 B1 Solids Content (%) 14.50 C1 183.00 D1 Dirty condensate flow (lb/hr) 21380.8 Heat vap out (Btu/lb), λ Temperature (°F) ect 3
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stants for equations: Heat Vap. (Btu/lb)
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This note was uploaded on 02/07/2011 for the course PSE 417 taught by Professor Kirkman during the Fall '10 term at N.C. State.

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RusliWPS 417 - Problem 3 - Multiple Effect Evaporators - GRADED

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