209s10a5s

209s10a5s - C & 20.0 MPa. In each case, what is the...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
DCGN209-Spring’10: Homework#4 p. 1 of 1 I. to hand in) . Use the following table when appropriate. Substance T C (K) P C (MPa) He 5.19 0.227 H 2 32.97 1.293 N 2 126.21 3.39 O 2 154.89 5.043 C O 2 303.14 7.375 A. For each of the following gases briefly explain why that gas can be treated (to first approximation) as an ideal gas at 25.0 0 C & 0.700 bar. Dominant Reason 1. H e T R >> 2 2. CO 2 P R = 0.0095 < 0.01 B. Use the generalized compressibility chart to estimate Z, then estimate the volume occupied by 0.654 moles of the following gases at –50.0
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: C & 20.0 MPa. In each case, what is the dominant reason for non-ideal behavior? ~Z Reason V (m 3 ) 1. H 2 1.20 size/repulsion 7.28x10-5 . 2. O 2 0.75 attraction 4.55x10-5 . II. Hand-In Problems Due: 2:00 PM, Wednesday February 17, 2010 A. (10 pts) The dominant component of air is N 2 . Explain as completely as you can, why air (i.e. N 2 ) can, to a first approximation can be considered an ideal gas at 25.0 C & 1.00 bar. B. (15 pts) Calculate the volume occupied by 0.654 moles of N 2 (g) at –65.0 C & 10.0 MPa....
View Full Document

This note was uploaded on 02/08/2011 for the course DCGN 209 taught by Professor Simmons,e during the Spring '08 term at Mines.

Page1 / 4

209s10a5s - C & 20.0 MPa. In each case, what is the...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online