IE_111_Spring_2011-_HW_2

IE_111_Spring_2011-_HW_2 - IE 111 Spring 2011 HW #2...

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IE 111 Spring 2011 HW #2 Problems: 2-42, 2-44, 2-50, 2-52, 2-58, 2-74, 2-80, 2-84, 2-90, 2-96 Solutions: 2-42. a) If the chips are of different types, then every arrangement of 5 locations selected from the 12 results in a different layout. Therefore, 040 , 95 ! 7 ! 12 12 5 = = P layouts are possible. b) If the chips are of the same type, then every subset of 5 locations chosen from the 12 results in a different layout. Therefore, ( 29 792 ! 7 ! 5 ! 12 12 5 = = layouts are possible. 2-44. a) Every arrangement selected from the 12 different components comprises a different design. Therefore, 600 , 001 , 479 ! 12 = designs are possible. b) 7 components are the same, others are different, 95040 ! 1 ! 1 ! 1 ! 1 ! 1 ! 7 ! 12 = designs are possible. c) 3326400 ! 4 ! 3 ! 12 = designs are possible 2-50. a) A B = 56 b) A = 36 + 56 = 92 c) A B = 40 + 12 + 16 + 44 + 56 = 168 d) A B = 40+12+16+44+36=148 e) A B = 36 2-52. a) A B = 1277 b) A = 22252 – 5292 = 16960
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IE_111_Spring_2011-_HW_2 - IE 111 Spring 2011 HW #2...

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