IE_111_Spring_2011-_HW_2

IE_111_Spring_2011-_HW_2 - IE 111 Spring 2011 HW#2 Problems...

This preview shows pages 1–2. Sign up to view the full content.

IE 111 Spring 2011 HW #2 Problems: 2-42, 2-44, 2-50, 2-52, 2-58, 2-74, 2-80, 2-84, 2-90, 2-96 Solutions: 2-42. a) If the chips are of different types, then every arrangement of 5 locations selected from the 12 results in a different layout. Therefore, 040 , 95 ! 7 ! 12 12 5 = = P layouts are possible. b) If the chips are of the same type, then every subset of 5 locations chosen from the 12 results in a different layout. Therefore, ( 29 792 ! 7 ! 5 ! 12 12 5 = = layouts are possible. 2-44. a) Every arrangement selected from the 12 different components comprises a different design. Therefore, 600 , 001 , 479 ! 12 = designs are possible. b) 7 components are the same, others are different, 95040 ! 1 ! 1 ! 1 ! 1 ! 1 ! 7 ! 12 = designs are possible. c) 3326400 ! 4 ! 3 ! 12 = designs are possible 2-50. a) A B = 56 b) A = 36 + 56 = 92 c) A B = 40 + 12 + 16 + 44 + 56 = 168 d) A B = 40+12+16+44+36=148 e) A B = 36 2-52. a) A B = 1277 b) A = 22252 – 5292 = 16960

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/07/2011 for the course IE 111 taught by Professor Storer during the Spring '07 term at Lehigh University .

Page1 / 2

IE_111_Spring_2011-_HW_2 - IE 111 Spring 2011 HW#2 Problems...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online