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Unformatted text preview: Find initial mass of liquid and vapor g g cm cm x m cm m v Vol m g g cm cm x v Vol m g g g f f f 985 / 8 . 605 10 3 1 10 6 . 2796 / 073 . 1 10 3 3 3 3 3 3 6 3 1 1 1 3 3 3 1 1 1 = − ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ = = = = = Total mass = 3781g and the initial specific volume is 0.1587 m3/kg. And, the initial quality and enthalpy are: Office of Industrial Productivity and Energy Assessment Michael R. Muller, Director kg kJ h m m m g f g / 8 . 1123 2 . 561 * ) 26 . 1 ( 9 . 2724 * 26 . % 26 985 2796 985 1 1 1 1 = − + = = + = + Final specific volume is the same as the initial. This equates to the pressure where v g = 0.1587 m 3 /kg which is 1.24 MPa Final enthalpy = h g = 2787 kJ/kg, so Δ h=1663 kJ/kg * 3.781kg = 6287 kJ...
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This note was uploaded on 02/08/2011 for the course ME 650:462 taught by Professor Muller during the Fall '10 term at Rutgers.
 Fall '10
 Muller
 Heat Transfer

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