2010quiz1 - Find initial mass of liquid and vapor g g cm cm...

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Center for Advanced Energy Systems Michael R. Muller, Director 640 Bartholomew Road, Piscataway NJ 08854 (908) 644-8469 FAX: (732) 445-0730 [email protected] http://caes.rutgers.edu 650:462 Power Plants Quiz 1 NAME: __________________________ September 22, 2010 Open books, notes A closed, rigid tank of volume 0.6 m 3 contain a two-phase liquid-vapor mixture of H 2 0 at 300 kPa. The volume occupied by saturated liquid is 3 x 10 3 cm 3 . Heat transfer takes place to the contents of the tank until all of the liquid is vaporized and only saturated vapor is present. Determine the final pressure, in kPa, and the amount of heating needed in kJ. Figure is NOT to scale! Solution: a) volume is constant, mixture specific volume is constant, pressure changes. b) quality is based on mass, not volume.
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Unformatted text preview: Find initial mass of liquid and vapor g g cm cm x m cm m v Vol m g g cm cm x v Vol m g g g f f f 985 / 8 . 605 10 3 1 10 6 . 2796 / 073 . 1 10 3 3 3 3 3 3 6 3 1 1 1 3 3 3 1 1 1 = − ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ = = = = = Total mass = 3781g and the initial specific volume is 0.1587 m3/kg. And, the initial quality and enthalpy are: Office of Industrial Productivity and Energy Assessment Michael R. Muller, Director kg kJ h m m m g f g / 8 . 1123 2 . 561 * ) 26 . 1 ( 9 . 2724 * 26 . % 26 985 2796 985 1 1 1 1 = − + = = + = + Final specific volume is the same as the initial. This equates to the pressure where v g = 0.1587 m 3 /kg which is 1.24 MPa Final enthalpy = h g = 2787 kJ/kg, so Δ h=1663 kJ/kg * 3.781kg = 6287 kJ...
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This note was uploaded on 02/08/2011 for the course ME 650:462 taught by Professor Muller during the Fall '10 term at Rutgers.

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2010quiz1 - Find initial mass of liquid and vapor g g cm cm...

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