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Unformatted text preview: Solution: Find Total Enthalpy change for steam hin = 68.79 Btu/lbm and hout = 1368.9 Btu/lbm Enthalpy for saturated liquid = 394 Btu/lbm (sat temp = 417.35 F) Given the flow rate, total energy transfer is: 19,501 Btu/min For air side, with given mass flow rate, total change in enthalpy should be: 91.98 Btu/lbm Inlet enthalpy = 342.9 Btu/lbm Exit enthalpy = 250.95 - exit air temp = 581 F Pinch Point occurs where water starts to boil. Enthalpy difference there is 1368.9-394 = 974.9 Btu/lbm or 14623 Btu/min For Air this means a drop in enthalpy of 14623/212 = 68.98 or an enthalpy of 342.9-68.98 = 273.92 Btu/lbm or a temp of approx 669 F Pinchpoint = 669-417.35= 251.65 F...
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This note was uploaded on 02/08/2011 for the course ME 650:462 taught by Professor Muller during the Fall '10 term at Rutgers.
- Fall '10