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Unformatted text preview: MATH 55 MIDTERM 1, FALL 2010 (1) YOUR NAME: (2) Indicate which section you are in, below. square 8-9am, 151 Barrows, Noah Forman square 9-10am, 3102 Etcheverry, Charles Crissman square 10-11am, 130 Wheeler, Charles Crissman square 10-11am, 122 Barrows, Noah Forman square 12-1pm, 3109 Etcheverry, Rob Bayer square 1-2pm, 85 Evans, Rob Bayer square 3-4pm, 385 Leconte, Charles Crissman square 4-5pm, 183 Dwinelle, Rob Bayer (3) SCORE (each problem worth 25 points) Problem Score 1. 2. 3. 4. TOTAL 1 2 MATH 55 MIDTERM 1, FALL 2010 (1) Let J ( x ) , M ( x ) , B ( x ) be the statements “ x is a jabberwocky,” “ x is manx- ome,” and “ x is beamish.” Express each of statements (a), (b), (c), using quantifiers; logical connectives; and J ( x ), M ( x ), B ( x ), where the domain consists of all creatures, real and imaginary. Then answer (d). Note: for the purpose of this exam, a jabberwocky is a creature. (a) No jabberwockies are manxome. (b) All manxome creatures are beamish. (c) No jabberwockies are beamish. (d) Does (c) follow from (a) and (b)? Solution : For parts (a), (b) and (c), many equivalent solutions would be acceptable. Below, I’ve listed one of the most literal solutions for each part....
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- Fall '08
- Math, Natural number, Euclidean algorithm, Rob Bayer, Charles Crissman