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182-2010-ps6KEY

182-2010-ps6KEY - STUDENT NAME LAB DAY 20182-2010-problem...

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Unformatted text preview: STUDENT NAME __________________________________ LAB DAY___________ 20182-2010-problem set 6: Yeast Genetics 1. You carry out a genetic screen to identify yeast mutants that are unable to grow in the absence of asparagine (Asp- ). You mutagenize a MATa ura3 strain as well as a MAT α ura3 strain and plate for single colonies on rich medium (YPD medium*). You then replica plate your colonies to minimal synthetic medium containing Ura but lacking Asp and look for colonies that fail to grow. You obtain 42 Asp- colonies from the MATa strain and 64 Asp- colonies from the MAT α strain. You then mate cells from your colonies in all possible combinations and obtain the following results: 20 of the MATa Asp- strains ( MATa class 1) yield diploids that can grow on medium without Asp when mated to any one of 40 of the MAT α strains, but not when mated to any of the remaining 24 MAT α strains. You call these 40 MAT α strains “MAT α class A.” The remaining 22 MATa strains ( MATa class 2) do not produce Asp + diploids when mated to MAT α class A strains, but produce only Asp + diploids when mated to any of the other 24 MAT α Asp- strains (MAT α class B). From this analysis how many complementation groups to your 106 Asp- mutants represent? (*YPD stands for y east extract, p eptone, d extrose) There are 2 complementation groups Class 1. (20 MATa class 1 + 24 MAT α class B )=44 Complementation group I...
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182-2010-ps6KEY - STUDENT NAME LAB DAY 20182-2010-problem...

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