Vibrations(2.34)

Vibrations(2.34) - to be spring force. The spring force has...

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Problem 2.34 (Ehsan Mohammadi) clc;clear m = 10; %kg k = 1500; %N/m c = 2500; %N/(m/s) syms t x = 0.2*sin(9*t); dx = 0.2*9*cos(9*t); ddx = 0.2*9*9*-sin(9*t); subplot(3,1,1) ezplot(k*x, [0 5]) ylabel('k*x (N)') xlabel('time (s)') title('x vs time') hold on subplot(3,1,2) ezplot(c*dx, [0 5]) xlabel('time (s)') ylabel('c*dx (N)') title('dx vs time') hold on subplot(3,1,3) ezplot(m*ddx, [0 5]) xlabel('time (s)') ylabel('m*ddx (N)') title('ddx vs time') hold on
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It can be shown that all the units will simply become Newton. This is an indication that the equation and the units are correct. From examining of the first graph which is (x vs time) it is simply shown that the mass is going through an isolating force which is known
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Unformatted text preview: to be spring force. The spring force has amplitude of 300N. By examining the second graph (dx vs time) we can clearly see that the second graph is the derivative of the first graph. The isolating force which is depicted in the graph is known to be the damper force which has amplitude of 4500N. The Last graph (ddx vs time) is the derivative of the first graph or the second derivative of the first graph. This graph is known to be the translational motion. This graph is also depicting isolating force acting on the mass that is being isolated. The amplitude of this graph is 162N....
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This note was uploaded on 02/13/2011 for the course ENME 361 taught by Professor Yoo during the Spring '11 term at Maryland.

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Vibrations(2.34) - to be spring force. The spring force has...

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