ANSFB - E C E 4 1 7 5 B F in a l 1 2 -1 1 -0 8 E I GH T PR...

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ECE 4175B Final 12-11-08 Page 1 of 3 High 100 EIGHT PROBLEMS Upper quarter 91 Open book, open notes Median 81 Lower quarter 74 Low 31 1. [ ] I have completed the CIOS course evaluation. [5%] [ ] I have not completed the CIOS course evaluation. 2. As pointed out at the end of Section 17.1, the AD5602 is a digital-to-analog converter with the same functionality as the AD5601. But where the AD5601 has the SPI interface discussed in section 17.4, the [15%] AD5602 has an I C interface. 2 a. Showing all work clearly and referring to Figure 17-9, determine as well as you can the time that the Qwik&Low board would take to change the output of the AD5601. The approximate cycle count is 1+1+1+1+1+8+(1 to 3)+1+8+(1 to 3)+1 = 26 to 30 cycles or about 28 : s. Or (2 bytes x 8 : s/byte) plus an extra 12 : s or so. b. Again showing all work clearly, determine as well as you can the time that the 690 chip on your protoboard would take to change the output of the AD5602. Assume that the I C transfers proceed at the 100 kHz rate 2 specified by the I C standard. 2 The approximate time to send address byte and two data bytes is 10 : s/bit x 9 bits/byte x 3 bytes or about 270 : s. 3. For your design project, you used the pulse from the 4321 microcontroller to awaken the 690 [10%] microcontroller. a. Assume that your 690 code did this by invoking interrupt vectoring. Describe what lines had to be in your code to do this including any dealings with the watchdog timer. First thing in the interrupt service routine, reset the watchdog timer so that the
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ANSFB - E C E 4 1 7 5 B F in a l 1 2 -1 1 -0 8 E I GH T PR...

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