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hw10-10sol - HW“\O scum-10119*4—64 The center post B of...

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Unformatted text preview: HW“ \O - scum-10119 *4—64. The center post B of the assembly has an original length of 124.7 mm, whereas posts A and C have a length of 125 m. If the caps on the top and bottom can be considered rigid, determine the average normal stress in each post. The posts are made of aluminum and have a . cross-sectional area of 400 m2. Ed = 70 GPa. C+2MB = 0; ‘FA(100) + Fc(100) = 0 FA = FC = F +12F, = o; 2F + F3 —. 160 = o ' CLQMAARAU M] 5,, = 5,, + 0.0003 Lawfmfilmrfl ' F 0.125 F 0.1247 ' ' . ( ) 3( ) + 00003 400 (10-6)(70)r(10°) = 400 (10-5)(70)(106) ' 0.125 F - 0.1247175 = 3.4 ' Solving Eqs. (2) and (3) F = 75.762 kN FB = 8.547 kN 75.726 (103) «A = ac=————= 189MPa 400(10-5) 8.547 (103) 0'3 = —5 = 21.4 MPa 400 (10 ) W11 ll. 0131... “1.1.1“ (1.3.. 0.1101. m 01/... 12,111.10. 0.1? 1,211.?) M 'OS‘R'A‘X: * fiwchN/nLDiJ/Q 3 <60 W V U <60M01251 AWEZFGOW‘M' 9111A£¢Lw BA: ARA : :_ kvwfl {Lamb MAM? ”M21001 mix. mic-hat A 0.0004,: (10‘000‘000 7“ [Mb W (1) (2) ' (3) SIM—f: E 3/7] w?) 2 0.0003 5714 ‘5 0:58.11»! UL \ I “MA JILL 90.91 “to 0 111/141. '2. 7%»me ARM @wa) wad: A560 shad v (on \z 0L -. 1,.‘3x\.o"/ev “4%“ E» Moos \u; 9’1; 4w; LN“ (9% WM“: Am ’ firm: {a Tum“? T;— 10" F MD: 07m souffle“! AT: Tz-T‘z ”MW—10°F: 105°; m MW Myra“ a“ w. r} M 4+ \ij m SAL. % MA A- w W” m m 32m Mu mm g. (MW/u: (gym gm» : Sm "“ %MA& 93 3 ol— ULT) L”, -- FJ; ‘ : L~ 0L. LBW-3H,?“ ; 1.5L” @‘W'Vflwsm(wan/m z “Emilia Efififll- (3.53311 (”how ‘43 ‘F = Q5 x \0'” MM»? PW ERW— (3)3 WM“ 10%?) V: “1.) <6 \dvs 0’ :_ '\\-7J.<l(\¢ 1 S ~5ch £1 4 ~ ,_ (6“! z 419109!) HQ 53)“ L15 1Q 1 \x 4-87. Determine the maximum normal stress developed in the bar when it is subjected to a tension of P = 8 kN. For the fillet: Q 10 w r 7—20‘2 2‘ 0"0'5 From Hg. 1024. K = 1.4 Umax = Kaavg 8 1 = (___< 03> ) 0.02 (0.005) = 112 NlPa For the hole: r 10 E ‘ 40 ‘ 0'25 From Fig. 4-25. K = 2.375 a'max = Kaavg = 2.375 (fl) (0.04 —— 0.02)(0.005) = 190MPa 4-90. The A-36 steel plate has a thickness of 12 m. If there are shoulder fillets at B and C, and O'auow = 150 MPa, determine the maximum axial load P that it can support. Calculate its elongation, neglecting the effect of the fillets Maximum Normal Stress at fillet: w 120 and z—T—Z From the text, K = 1.4 amax = o'allow = Kaavg ‘ _ __’_’__ 150006) ' 1'4[0.06(0.012)] ' P = 77142.86 N = 77.1 kN Displacement: 5:227; _ ’77142.86(400) '+ 77142.86(800) ,— (0.06)'(0.012)(200)(109) (0.12)(o.012)(200)(109) = 0.429 mm ...
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