4_example_KVL_02

4_example_KVL_02 - KIRCHOFF’S VOLTAGE LAW EXAMPLE 2 GIVEN...

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Unformatted text preview: KIRCHOFF’S VOLTAGE LAW: EXAMPLE 2 GIVEN: Consider the circuit shown, where R1=12Ω R2=4Ω R3=12Ω V1=12V REQUIRED: (a) The current through R1. (b) The current through R2. (c) The current through R3. SOLUTION: (a) First, we identify the loops in the circuit. As shown below, we can choose any two of the three loops. Kirchoff’s Voltage Law: The sum of the voltage drops around any closed loop is zero. Applying KVL to Loop 1: Unfortunately, we have one equation with two unknowns (IR1 and IR2). Note that IR1 IR2 because IR1 splits between two resistors (R2 and R3). Students often do not recognize that the current SPLITS in this way. Find Req for the circuit so that we can find IR1: Apply Ohm’s Law: (b) Now that we know the current through R1, we can use KVL around Loop 1 (as shown earlier): (c) Apply KVL to Loop 3: DISCUSSION: • We can apply KVL to Loop 2 to check our work: Look at a voltage and current balance: Notice that when the current splits at node A, more current goes through R2 (4Ω) than through R3 (12Ω). Electricity takes the path of least resistance. • • ...
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This note was uploaded on 02/08/2011 for the course ENGR 120 taught by Professor Hall during the Winter '08 term at LA Tech.

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