Unformatted text preview: checked the nullclines for y. If y > 0, then dy dt = 0 ⇒ N = ma b-m (3) So the phase plane hasn’t changed much – the second nullcline for y is still a vertical line. Not only that, but in eq. (1) we got to choose our parameter d = bk . If k = c ( b-m ) bma (4) then the second y nullcline is still x = c/d , which is a lot easier to write. 1...
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- Fall '10
- Trigraph, Lotka–Volterra equation, phase plane, dy ma =0⇒N