project

project - Problem 1 1. The signal can be divided into...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Problem 1 1. The signal can be divided into (14000 samples)/(175 samples/frame)= 80 frames. As each frame is 20ms, the duration of the entire speech signal is 80 frames*20ms/frame = 1600 ms = 1.6 s. The original continuous-time speed signal sampled at 14000 samples/1.6s = 8750 samples/second. 2.∑ k=1 N 1 2 =N, N/N=1,the largest average power is 1 k=1 N (0.2) 2 =0.04N,N=175,0.04×175=7,the largest power is 7 3. Female 1: 0.71×175×0.015+0.12×175×0.025+0.02×175×0.035+0.02×175×0.045+0.02×175×0.055+0.02 ×175×0.065+0.01×175×0.075+0.04×175×0.085+0.01×175×0.095+0.02×175×0.105+0.01×175× 0.115= Male 2: 0.62×175×0.015+0.11×175×0.025+0.12×175×0.035+0.07×175×0.045+0.04×175×0.055+0.03× 175×0.065+0.01×175×0.075= 4. The proportion for female 1 is 0.29, female 2 is 0.53, male 1 is 0.18, and male 2 is 0.38. Therefore, we conclude that female 2 has the most voiced frames while male 1 has the least. Problem 2 Time and Frequency Representations Exercises 1. Adding two sinusoids with nearly identical frequencies produces beat notes. For example, we can produce beat frequencies by playing two neighboring notes of a piano simultaneously, say The two frequencies f 1 and f 2 can be expressed in terms of a center frequency fc and a deviation frequency,
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Using the complex representation of cosines, show that we can rewrite x(t) as Using this formula, explain why we refer to this signal as Amplitude Modulated (AM). You can see this effect by choosing the beat sound in the experiment. Determine the frequencies that were used to generate this beat sound. This signal is Amplitude Modulated because we are varying the amplitude of the contents while keeping the frequency constant at a modulated frequency The beat sound was generated at ≈ 350Hz 2. Which sound in the experiment displays wide frequency content in its spectrogram at a particular instant of time. The dropping of eggs experiment displayed wide frequency content at about 0.9 seconds which ranges from 100Hz to 3700Hz. 3. What is the time span of the drop of the egg ? Knowing that the signal has been sampled at 8192 samples/second, how many samples were used to represent the drop of the egg ? The time span is about 1.22 seconds. Samples: 8192*1.22s = 9994.24 ≈ 10000samples 4. Compare the spectrograms of the Bird chirps sound and the Train whistle sound.
Background image of page 2
Comparing the two sounds’ spectrogram, the Bird chirps have similar frequency contents repeating over time, and the Train whistle display constant frequency contents over time. Moreover, observing at the spectrum plot, the Bird chirps have overall same average amplitude at different frequency and the Train whistle have overall constant amplitude at over the frequency spectrum. 5.
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 28

project - Problem 1 1. The signal can be divided into...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online