BIOL 2153
Sept 7
Read Ch. 3
No class Oct 3 & 5
1.
For a set of biallelic genes in which one of the alleles is completely dominant
over the other (must be heterozygous)
a.
# of possible phenotypes is 2
n
, where n is the # of genes
AABbCc = 2
2
= 4
2.
To calculate the number of gametes, multiply the number of possible gametes for
each gene
Aa= 2
Bb=2
2x2=4 gametes
AaBBCcdd = 4 gametes (for each gene decide how many types of gametes it can
produce homozygous can only produce one)
3.
Probability Rules
a.
Product rule
 states that the probability of 2 or more independent events
occurring together is the product of the probabilities that each event will occur
by itself
prob (h)= ½
prob (t)= ½
prob (h,t) and (t, h) ¼ + ¼ = ½
b.
Sum rule
 states that the probability of either of two mutually exclusive events
is the sum of their individual probabilities.
Problem 210 : what is the probability of rolling a 6? 1/6
*What is the probability of rolling an even number? 3/6
2 : 1/6
4: 1/6
mutually exclusive: added equals 3/6
6: 1/6
*What’s the probability for rolling a # divisible by 3? 1/6 + 1/6 = 1/3
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
This is the end of the preview.
Sign up
to
access the rest of the document.
 Spring '08
 SILLS
 Probability, #, Punnett square

Click to edit the document details