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Unformatted text preview: The problem is Binomial with n = 34 and p = 1/2)P(x = 22) = binomcdf(34,0.5,22) = 0.031918406 Best Answer  Chosen by Voters 1. mean = .5 * 2 + .3 * 8 + .2 * 10 = 5.4 variance = .5 * (2  5.4)^2 + .3 * (8  5.4)^2 + .2 * (10  5.4)^2 = 12.04 2. P(all tenured) = 6 / 8 * 5 / 7 * 4 / 6 = 5 / 14 P(at least one not tenured) = 1  P(all tenured) = 11 / 14 5. (1 / 2)^29 * (1/2)^5 * 34C29 = 0.000016197 Sheet1 Page 2 that is, the probability it is either up or down is 0.5....
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This note was uploaded on 02/10/2011 for the course STAT MC101 taught by Professor Yabada during the Spring '09 term at Adrian College.
 Spring '09
 YABADA

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