Exam 1 - Version 458 – Exam 1 – Mccord –(50970 1 This...

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Unformatted text preview: Version 458 – Exam 1 – Mccord – (50970) 1 This print-out should have 31 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points How many electrons can possess this set of quantum numbers: principal quantum num- ber n = 4, angular quantum number ℓ = 2? 1. 8 2. 14 3. 4 4. 10 correct 5. 16 6. 2 7. 6 8. 12 9. 18 10. Explanation: Use the rules for the quantum numbers: If n = 4 and ℓ = 2 ( i.e. , 4 d ), then m ℓ =- 2 ,- 1 , , +1 , +2 are permitted; there are five different orbitals and m s = ± 1 2 , each holding two electrons. 002 10.0 points An electron in a 3 d orbital could have which of the following quantum numbers? 1. n = 3; ℓ = 2; m ℓ =- 3 2. n = 2; ℓ = 3; m ℓ = 0 3. n = 3; ℓ = 1; m ℓ =- 1 4. n = 3; ℓ = 3; m ℓ = 1 5. n = 2; ℓ = 2; m ℓ = 2 6. n = 3; ℓ = 0; m ℓ = 0 7. n = 3; ℓ = 2; m ℓ = 0 correct Explanation: 3 refers to the principal quantum number n . d corresponds to the subsidiary quantum number ℓ = 2. Since ℓ = 2, m ℓ could be- 2 ,- 1 , , 1 or 2. 003 10.0 points Write an equation for the second ionization energy of calcium. 1. Ca + (g) + e- → Ca- (g) 2. Ca + (g) + 2 e- → Ca 2+ (g) 3. Ca + (g) + e- → Ca(g) 4. Ca + (g) → Ca 2+ (g) + e- correct 5. Ca(g) → Ca 2+ (g) + 2 e- Explanation: Definition 004 10.0 points Which of the following best describes the range of atomic radii? 1. 1 to 100 ˚ A 2. 5 to 10 ˚ A 3. 1 to 15 ˚ A 4. 0.4 to 3 ˚ A correct 5. 10 to 30 ˚ A 6. 0.05 to 1 ˚ A Explanation: Atomic radii vary from 30 pm (He) to 300 pm (Fr). 1 ˚ A= 10- 10 m = 100 pm, so the range of atomic radii is 0.3 to 3 ˚ A. 005 10.0 points Version 458 – Exam 1 – Mccord – (50970) 2 The higher the energy of electromagnetic ra- diation, the 1. longer its wavelength. 2. shorter its wavelength. correct 3. greater its mass. 4. higher the velocity of light. 5. lower its frequency. Explanation: For electromagnetic radiation, the energy of radiation is related to its frequency by the equation E = h ν , where h is Planck’s constant, ν = c λ , and c is the speed of light in a vacuum (also a constant). Thus, the equation that relates energy to wavelength for electromagnetic radiation is E = h c λ As energy increases, ν (frequency) must also increase, and λ (wavelength) must decrease. 006 10.0 points Write the ground-state electron configuration of a lead atom. 1. [Xe] 4 f 14 5 d 9 6 s 2 6 p 3 2. [Xe] 4 f 14 5 d 10 6 s 2 6 p 2 correct 3. [Xe] 4 f 14 5 d 10 6 p 4 4. [Xe] 4 f 14 5 d 5 6 s 1 6 p 6 7 s 2 5. [Xe] 4 f 14 5 d 10 6 s 1 6 p 3 Explanation: The Aufbau order of electron filling is 1 s , 2 s , 2 p , 3 s , 3 p , 4 s , 3 d , 4 p , 5 s , 4 d , 5 p , 6 s , 4 f , 5 d , 6 p , etc ....
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This note was uploaded on 02/10/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas.

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Exam 1 - Version 458 – Exam 1 – Mccord –(50970 1 This...

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