HW 2 - johnson(mjj622 HW 2 Coker(56625 This print-out...

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johnson (mjj622) – HW 2 – Coker – (56625) 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. In class we did not cover the part of Ch. 3 dealing with vector products, and vector products will not be covered on this home- work or on Quiz 1. Vector products will be in- troduced in later chapters as they are needed for the concepts of work and torque. 001 10.0 points A hiker makes three straight-line walks A 16 km at 301 B 19 km at 359 C 31 km at 81 in random directions and lengths starting at position (41 km , 41 km) , listed below and shown below in the plot. A B C Scale: 10 km = Figure: Drawn to ok. Which vector will return the hiker to the starting point? All angles are measured in a counter-clockwise direction from the positive x -axis. 1. bardbl vector D bardbl = 32 . 2631 km , θ d = 273 . 996 2. bardbl vector D bardbl = 26 . 5131 km , θ d = 172 . 211 3. bardbl vector D bardbl = 22 . 5473 km , θ d = 301 . 08 4. bardbl vector D bardbl = 60 . 135 km , θ d = 104 . 162 5. bardbl vector D bardbl = 12 . 3751 km , θ d = 290 . 007 6. bardbl vector D bardbl = 36 . 114 km , θ d = 207 . 315 cor- rect 7. bardbl vector D bardbl = 32 . 5179 km , θ d = 206 . 246 8. bardbl vector D bardbl = 4 . 4293 km , θ d = 167 . 501 9. bardbl vector D bardbl = 20 . 6618 km , θ d = 22 . 4451 10. bardbl vector D bardbl = 45 . 172 km , θ d = 131 . 966 Explanation: Δ a x = (16 km) cos 301 = 8 . 24064 km , Δ a y = (16 km) sin 301 = 13 . 7147 km , Δ b x = (19 km) cos 359 = 18 . 9971 km , Δ b y = (19 km) sin 359 = 0 . 331545 km , Δ c x = (31 km) cos 81 = 4 . 84945 km , Δ c y = (31 km) sin 81 = 30 . 6183 km , A B θ d C D Scale: 10 km = Δ x = Δ a x + Δ b x + Δ c x = 8 . 24064 km + (18 . 9971 km)
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johnson (mjj622) – HW 2 – Coker – (56625) 2 + (4 . 84945 km) Δ y = Δ a y + Δ b y + Δ c y = 13 . 7147 km + ( 0 . 331545 km) + (30 . 6183 km) The resultant is D = radicalBig x ) 2 + (Δ y ) 2 = radicalBig (73 . 0872 km) 2 + (57 . 5721 km) 2 θ D = arctan vextendsingle vextendsingle vextendsingle vextendsingle 57 . 5721 km (41 km) 73 . 0872 km (41 km) vextendsingle vextendsingle vextendsingle vextendsingle = 207 . 315 . 002 (part 1 of 2) 10.0 points Consider two vectors where F 1 = 80 N , F 2 = 72 N , θ 1 = 61 C , and θ 2 = 298 C , measured from the positive x axis with the counter- clockwise angular direction as positive. What is the magnitude of the resultant vec- tor vector F = vector F 1 + vector F 2 ?
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