solution_3pdf - armington(kma786 hw0201 ete(57165 This...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
armington (kma786) – hw0201 – fete – (57165) 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points IF you drop an object, it will accelerate down- ward at a rate oF g = 9 . 8 m / s 2 . IF you throw it downward instead, its accel- eration (in the absence oF air resistance) will be 1. less than 9 . 8 m / s 2 . 2. 9 . 8 m / s 2 correct 3. greater than 9 . 8 m / s 2 . 4. Unable to determine. Explanation: The acceleration due to the gravity is in- dependent oF any initial velocity and remains constant. 002 10.0 points A stone is thrown straight upward and at the top oF its trajectory its velocity is momentar- ily zero. What is its acceleration at this point? 1. 9.8 m/s 2 down correct 2. Unable to determine 3. 9.8 m/s 2 up 4. Zero Explanation: The gravitational acceleration near the sur- Face oF the earth is considered constant For all practical purposes. This acceleration oF 9.8 m/s 2 points downward. 003 10.0 points A basketball player achieves a hang time oF 0 . 94 s in dunking the ball. What vertical height will he attain? The acceleration oF gravity is 9 . 8 m / s 2 . Correct answer: 1 . 08241 m. Explanation: Let : t = 0 . 94 s and g = 9 . 8 m / s 2 . It takes the basketball player Δ t = t 2 to rise to his maximum height, defned by h = 1 2 g t ) 2 = g 2 t 2 4 = g t 2 8 = (9 . 8 m / s 2 ) (0 . 94 s) 2 8 = 1 . 08241 m . 004 10.0 points The acceleration oF a marble in a certain ±uid is proportional to the speed oF the marble squared, given by a = α v 2 , where v > 0 m/s and α = - 1 . 61 m 1 . IF the marble enters this ±uid with a speed oF 0 . 96 m / s, how long will it take beFore the marble’s speed is reduced to halF oF its initial value?
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 5

solution_3pdf - armington(kma786 hw0201 ete(57165 This...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online