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Unformatted text preview: , I D3 , I D4 for R 1 = 50k, R 2 = 40k, R 3 = 20k, R 4 = 40k. Fig. 3 4- An electrical engineering student has lost his 2.1-V cellphone charger and couldnt find an adaptor with output less than 3 V. He then decides to put his knowledge of electronics into action and constructs the circuit shown in Fig. 4, where three identical diodes in forward bias produce a total voltage of V out = 3V D 2.1V at T=300 o K and R sustains the remaining 900mV. Neglect the current drawn by the cellphone for the sake of simplicity. (a) Determine the diode saturation current, I s , so that V out =2.1V. Assume n=1. (b) Use the iterative-analysis procedure to compute V out at T=300 o K if the adaptor voltage, V ad , changes to 3.2V. (c) Repeat (b) with the aid of a small-signal analysis. R = 150 +-Cellphone Adaptor I D V ad = 3V I cell 0 +-V out Fig. 4 Due date: September 24, 2009 at 1:00pm. Late submission will not be accepted....
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This note was uploaded on 02/12/2011 for the course ECED 3201 taught by Professor Al-sankary during the Spring '11 term at Dalhousie.
- Spring '11