HW-01-solutions

HW-01-solutions - kuruvila (lk5992) HW-01 gokce (P111S11) 1...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: kuruvila (lk5992) HW-01 gokce (P111S11) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Consider the expression 2 radicalBigg g , where is length and g is gravitational acceleration in units of length divided by time squared. Evaluate its units. 1. m 2. m s 3. parenleftBig s m parenrightBig 2 4. m 2 5. s 2 6. s m 7. parenleftBig m s parenrightBig 2 8. s correct Explanation: [ ] = m and [ g ] = m s 2 . 2 and are constants, so radicalBigg [ ] [ g ] = radicalbigg m m s 2 = radicalbigg m s 2 m = s 2 = s . 002 10.0 points Rain drops fall on a tile surface at a density of 4584 drops / ft 2 . There are 11 tiles / ft 2 . How many drops fall on each tile? Correct answer: 416 . 727 drops / tile. Explanation: Let : = 4584 drops / ft 2 and n = 11 tiles / ft 2 . Applying dimensional analysis, R = n = 4584 drops / ft 2 11 tiles / ft 2 = 416 . 727 drops / tile . 003 10.0 points An electron travels 2 . 13 m in 6 . 4 s (microsec- onds). What is its speed if 1 inch = 0.0254 m? Correct answer: 7 . 86171 10 8 in / min. Explanation: Let : L = 2 . 13 m and t = 6 . 4 s = 6 . 4 10 6 s . The speed is v = L t = 2 . 13 m 6 . 4 10 6 s 100 cm 1 m 1 in 2 . 54 cm 60 s 1 min = 7 . 86171 10 8 in / min . 004 10.0 points A high fountain of water is located at the center of a circular pool as in the figure. A student walks around the pool and estimates its circumference to be 209 m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation of the top of the fountain to be 61 . 6 . How high is the fountain? Correct answer: 61 . 5194 m. Explanation: kuruvila (lk5992) HW-01 gokce (P111S11) 2 Let : C = 209 m and = 61 . 6 . R h The circumference of the pool is C = 2 R , so its radius is R = C 2 = 209 m 2 = 33 . 2634 m ....
View Full Document

Page1 / 5

HW-01-solutions - kuruvila (lk5992) HW-01 gokce (P111S11) 1...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online