PS5-08-Solution - Chem 442B Homework Set #5 - Solutions...

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Chem 442B Homework Set #5 - Solutions DUE: Tuesday, November 11, 2008 1) () 22 1/4 6 /2 1 1 2 2 4 (pg 170 McQ&S) is the value of x where the potential energy = the total energy 1 1 2 11 31 33 recall 3 Total proba x m m m m xx e x E Vx k x m x mx m x m x β π ω ωω ωβ ⎛⎞ Ψ= ⎜⎟ ⎝⎠ =+ == = = = = = = = 2 1 1/2 66 3/ 2 1 6 2 0 2 1 bility in forbidden region = 1- 44 4 2 / upper limit changes to 3 m m mm x x x dx dx xe Let y x x y dy dy dx dx dx ββ ππ −− Ψ = = =→ = =→= Ψ ∫∫ 2 2 62 3 2 0 3 2 0 2 1 4 2 0.393657 0.88839 Total probability in forbidden region = 1- 1 0.88839 0.1116 m m m m x y x y x x yd y e ye dy dx πβ = = = Problem Set #5 Solution - 1 -
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2)a) McQ&S 5-34 () 1 222 2 34 21 1 10 2 47 2 27 2 27 47 2 2 Line separation 2 16.72 844 1 6.626 10 1 4 16.72 16.72 4 2.998 10 / 3.346 10 179 1.6605402 10 1.6398 10 17 9 3.346 10 hh h Bc cI cI c r hJ s I cc m c m cm s Ik g m kg m I rk amu g r πππ μ π μμ −− == = = = ×⋅ × × =→ = × = × + × ± g 2 20 2 27 o 10 2.0405 10 1.6398 10 1.428 10 1.428A m m kg rm × = b) 2 2 22 11 1 2 1 2 Line spacing = 2
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This note was uploaded on 02/12/2011 for the course CHEMISTRY 442 taught by Professor Lizzy during the Spring '10 term at Hanoi University of Technology.

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PS5-08-Solution - Chem 442B Homework Set #5 - Solutions...

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