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PS5-08-Solution - Chem 442B Homework Set#5 Solutions DUE...

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Chem 442B Homework Set #5 - Solutions DUE: Tuesday, November 11, 2008 1) ( ) ( ) 2 2 1/4 6 /2 1 1 2 2 2 2 2 2 2 2 4 (pg 170 McQ&S) is the value of x where the potential energy = the total energy 1 1 2 1 1 2 2 3 1 2 2 3 3 recall 3 Total proba x m m m m x xe x E V x kx m x m x m x m x β β π ω ω ω ω ω β ω β β Ψ = = + = = = = = = = = = = = 2 2 2 2 2 2 2 1 1/2 1/ 2 6 6 3 / 2 2 2 1 3 / 1/2 6 3 / 2 0 2 1 bility in forbidden region = 1- 4 4 4 2 / upper limit changes to 3 m m m m m m x x x x x x x x x dx dx x e dx x e dx x e dx Let y x x y dy dy dx dx dx β β β β β β β β π π β π β β β β Ψ Ψ = = = = = = = Ψ ( ) 2 2 1/2 6 2 3 2 0 3 2 0 2 1 4 2 4 4 0.393657 0.88839 Total probability in forbidden region = 1- 1 0.88839 0.1116 m m m m x y x y x x y dy e y e dy dx β π β β π π = = = = Ψ = = Problem Set #5 Solution - 1 -
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